Advertisements
Advertisements
प्रश्न
Let the resistance of an electrical device remain constant, while the potential difference across its two ends decreases to one fourth of its initial value. What change will occur in the current through it? State the law which helps us in solving the above stated question.
Advertisements
उत्तर
The change in the current flowing through the electrical component can be determined by Ohm's Law.
According to ohm's law i.e.,
V = IR
V: applied voltage
I: current
R: resistance
⇒ I = `"V"/"R"`
Now potential difference becomes one fourth,
V' = `"V"/4`
So current will be: I' =`(("V"//4))/"R"`
⇒ I' = `"v"/(4"R")`
⇒ I' = `"I"/4`
When the potential difference is one fourth, the current through the component also decreases to one fourth of its initial value.
संबंधित प्रश्न
What is an Ohmic resistor?
Fill in the following blank with suitable words:
Resistance is measured in .............. The resistance of a wire increases as the length ..............; as the temperature ..............; and as the cross-sectional area .............. .
State Ohm’s law and draw a neat labelled circuit diagram containing a battery, a key, a voltmeter, an ammeter, a rheostat and an unknown resistance to verify it.
Fig. represents the circuit used for the verification of ohm's law. Label the different parts from A and F. State the function of each.

What is meant by the drift speed of free electrons?
Define ampere and volt with respect to Ohm’s law.
Which of the following I-V graph represents ohmic conductors?
A heater of 220 V heats a volume of water m 5 mint time. A heater of 110 V heat in ten second. The resistance of the conductor is
The resistance of a resistor is reduced to half of its initial value. If other parameters of the electrical circuit remain unaltered, the amount of heat produced in the resistor will become ______.
