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प्रश्न
Let the resistance of an electrical device remain constant, while the potential difference across its two ends decreases to one fourth of its initial value. What change will occur in the current through it? State the law which helps us in solving the above stated question.
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उत्तर
The change in the current flowing through the electrical component can be determined by Ohm's Law.
According to ohm's law i.e.,
V = IR
V: applied voltage
I: current
R: resistance
⇒ I = `"V"/"R"`
Now potential difference becomes one fourth,
V' = `"V"/4`
So current will be: I' =`(("V"//4))/"R"`
⇒ I' = `"v"/(4"R")`
⇒ I' = `"I"/4`
When the potential difference is one fourth, the current through the component also decreases to one fourth of its initial value.
संबंधित प्रश्न
The relationship between the potential difference and the current in a conductor is stated in the form of a law.
- Name the law.
- What does the slope of V-I graph for a conductor represent?
- Name the material used for making the connecting wire.
Write the SI unit of resistivity
Name the physical quantity whose unit is "ohm".
The graph between V and I for a conductor is a straight line passing through the origin.
What should remain constant in a statement of this law?
In an experiment of verification of Ohm’s law following observations are obtained.
|
Potential difference V (in volt) |
0.5 | 1.0 | 1.5 | 2.0 | 2.5 |
| current I (in ampere) | 0.2 | 0.4 | 0.6 | 0.8 | 1.0 |
Draw a V-I graph and use this graph to find:
- the potential difference V when the current I is 0.5 A,
- the current I when the potential difference V is 0.75 V,
- the resistance in a circuit.
Define the following:
Coulomb
State and define Ohm’s law.
Define temperature coefficient of resistance.
Obtain the macroscopic form of Ohm’s law from its microscopic form and discuss its limitation.
A heater of 220 V heats a volume of water m 5 mint time. A heater of 110 V heat in ten second. The resistance of the conductor is
