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Find the principal solutions of cos 2ЁЭСе = 1
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cos 2x = 1
∴ cos 2x = cos (0) and cos 2x = cos (2π – 0) = cos 2π
such that 0 ≤ 0 < 2π and 0 ≤ π < 2π
∴ The required principal solutions are x = 0 and x = π.
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