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महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता १२ वी

Find the principal solution of the following equation: Sec θ = 23

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प्रश्न

Find the principal solution of the following equation: 

Sec θ = `(2)/sqrt(3)`

बेरीज
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उत्तर

We know the principle solution of a trigonometric equation lies in the interval (0, 2π).

For, sec θ = `2/(sqrt3)`,

we know sec θ is positive only in the 1st and 4th quadrant in the interval (0, 2π).
Now in the 1st quadrant,
sec θ = `2/(sqrt3) ⇒ θ = π/6`.

And, in 4th quadrant,
sec θ = `2/(sqrt3) ⇒ θ = 2π - π/6 = (11π)/6`.

Thus, the principle solution of the equation sec θ = `2/(sqrt3) "is"  θ = π/6 "and" (11π)/6`.

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पाठ 3: Trigonometric Functions - Exercise 3.1 [पृष्ठ ७५]

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बालभारती Mathematics and Statistics 1 (Arts and Science) [English] Standard 12 Maharashtra State Board
पाठ 3 Trigonometric Functions
Exercise 3.1 | Q 1.2 | पृष्ठ ७५

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