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Find the general solution of the following equation: sin 2θ = 12

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प्रश्न

Find the general solution of the following equation:

sin 2θ = `1/2`

बेरीज
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उत्तर

The general solution of sin θ = sin α is
θ = nπ + (– 1)nα, n ∈ Z.

Now, 

sin 2θ = `1/2`

∴ sin 2θ = `sin  pi/(6)                        ...[ ∵ sin  pi/(6) = (1)/(2)]`

∴ the required general solution is given by

2θ = nπ + (- 1)n  `(pi/6)`, n ∈ Z.

i.e. θ = `(npi)/(2) + (- 1)^n  (pi/12)`,n ∈ Z.

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पाठ 3: Trigonometric Functions - Exercise 3.1 [पृष्ठ ७५]

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बालभारती Mathematics and Statistics 1 (Arts and Science) [English] Standard 12 Maharashtra State Board
पाठ 3 Trigonometric Functions
Exercise 3.1 | Q 5.1 | पृष्ठ ७५

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