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Find the general solution of the following equation: cosec θ = - √2. - Mathematics and Statistics

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प्रश्न

Find the general solution of the following equation:

cosec θ = - √2.

बेरीज
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उत्तर

The general solution of sin θ = sin α is

θ = nπ + (–1)nα, n ∈ Z.

Now,

Cosec θ = - √2

∴ sin θ = `- (1)/sqrt(2)`        

∴ sin θ = `-sin  pi/(4)               ...[∵ sin  pi/(4) = (1)/sqrt(2)]` 

∴ sin θ = `sin(pi + pi/4)`    ...[ ∵ sin(π + θ) = – sin θ] 

∴ sinθ = `sin  (5pi)/(4)`         

∴ the required general solution is
θ = nπ + (-1)n `((5pi)/4)`, n ∈ Z.

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पाठ 3: Trigonometric Functions - Exercise 3.1 [पृष्ठ ७५]

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बालभारती Mathematics and Statistics 1 (Arts and Science) [English] Standard 12 Maharashtra State Board
पाठ 3 Trigonometric Functions
Exercise 3.1 | Q 4.2 | पृष्ठ ७५

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