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महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता १२ वी

Find the general solution of the following equation: sin θ = tan θ

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प्रश्न

Find the general solution of the following equation:

sin θ = tan θ

बेरीज
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उत्तर

sin θ = tan θ

tan θ = `sin theta/cos theta`

sin θ = `sin theta/cos theta`

Multiply both sides by cos⁡ θ

sin θ ⋅ cos θ = sin θ

sin θ cos θ − sin θ = 0

⇒ sin θ(cos θ − 1) = 0

sin θ(cos θ − 1) = 0

Case 1: sin⁡ θ = 0

sinθ = 0 ⇒ θ = nπ, where n ∈ Z

Case 2: cos⁡θ = 1

cos θ = 1

⇒ θ = 2nπ, where n ∈ Z

Consider excluded values (where cos⁡ θ = 0)

sin θ = `sintheta/costheta`

cos θ = 0

⇒ theta = `pi/2 + npi`, where n ∈ Z

θ = nπ, where n ∈ Z

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पाठ 3: Trigonometric Functions - Exercise 3.1 [पृष्ठ ७५]

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बालभारती Mathematics and Statistics 1 (Arts and Science) [English] Standard 12 Maharashtra State Board
पाठ 3 Trigonometric Functions
Exercise 3.1 | Q 7.1 | पृष्ठ ७५

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