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महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता १२ वी

Find the general solutions of the following equation: sin2 θ - cos2 θ = 1

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प्रश्न

Find the general solutions of the following equation:

sin2 θ - cos2 θ = 1

बेरीज
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उत्तर

sin2 θ - cos2 θ = 1

∴ cos2 θ - sin2 θ = - 1

∴ cos2θ  = cos π        .....(1)

The general solution of cos θ = cos α is

θ = 2nπ ± α, n ∈ Z.

∴ the general solution of (1) is given by

2θ = 2nπ ± π, n ∈ Z.

∴ θ = nπ ± `pi/2`, n ∈ Z

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Notes

The answer in the textbook is incorrect.

  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 3: Trigonometric Functions - Miscellaneous exercise 3 [पृष्ठ १०९]

APPEARS IN

बालभारती Mathematics and Statistics 1 (Arts and Science) [English] Standard 12 Maharashtra State Board
पाठ 3 Trigonometric Functions
Miscellaneous exercise 3 | Q 4.4 | पृष्ठ १०९

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