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Find the general solution of the following equation: 4 cos^2 θ = 3 - Mathematics and Statistics

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प्रश्न

Find the general solution of the following equation:

4 cos2 θ  = 3

बेरीज
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उत्तर

The general solution of cos2θ = cos2α is θ = nπ ± α, n ∈ Z.

Now, 4 cos2 θ  = 3

∴ `cos^2θ = (3)/(4) = (sqrt(3)/2)^2`

∴ `cos^2θ = (cos  π/(6))^2`   ...`[∵ cos  π/6 = sqrt(3)/(2)]`

∴ `cos^2θ = cos^2  π/6`

∴ The required general solution is given by `θ = nπ ± (π)/(6), n ∈ Z`.

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पाठ 3: Trigonometric Functions - Exercise 3.1 [पृष्ठ ७५]

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