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महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता १२ वी

Find the general solution of the following equation: cot 4θ = – 1

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प्रश्न

Find the general solution of the following equation:

cot 4θ = – 1

बेरीज
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उत्तर

The general solution of tan θ = tan α is
θ = nπ + α, n ∈ Z
Now, 

cot 4θ  = – 1

∴ tan 4θ = – 1

∴ tan 4θ = `– tan  pi/(4)     ...[ ∵ tan  pi/4 = 1]`

∴ tan 4θ  = `tan(pi - pi/4)`       ...[∵ tan(π – θ) = – tan θ]

∴ tan 4θ = `tan  (3pi)/(4)`

∴ the required general solution is given by

4θ =  `nπ +  (3pi)/(4), n ∈ Z`

i.e. θ = `(npi)/(4) + (3pi)/(16),n ∈ Z`.

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पाठ 3: Trigonometric Functions - Exercise 3.1 [पृष्ठ ७५]

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बालभारती Mathematics and Statistics 1 (Arts and Science) [English] Standard 12 Maharashtra State Board
पाठ 3 Trigonometric Functions
Exercise 3.1 | Q 5.3 | पृष्ठ ७५

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