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Find k, if the line 3x + 4y + k = 0 touches 9x2 + 16y2 = 144

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प्रश्न

Find k, if the line 3x + 4y + k = 0 touches 9x2 + 16y2 = 144

बेरीज
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उत्तर

We know that y = mx + c will touch the ellipse `x^2/"a"^2 + y^2/"b"^2` = 1

if c2 = a2m2 + b2    ...(1)

The equation of the line is

3x + 4y + k = 0

∴ y = `-3/4 "x" -"k"/4`

Comparing this equation with y = mx + c, we get,

m = `-3/4`, c = `-"k"/4`

The equation of the ellipse is 9x2 + 16y2 = 144

∴ `x^2/16 + y^2/9` = 1

Comparing this equation with `x^2/"a"^2 + y^2/"b"^2` = 1, we get

∴ a2 = 16, b2 = 9

Applying the tangency condition (1), we get,

`(-"k"/4)^2 = 16 xx (-3/4)^2 + 9`

∴ `"k"^2/16` = 9 + 9 = 18

∴ k2 = 16 × 9 × 2

∴ k = `±  12sqrt(2)`

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पाठ 7: Conic Sections - Exercise 7.2 [पृष्ठ १६३]

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