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Find the equation of the tangent to the ellipse 4x2 + 7y2 = 28 from the point (3, –2). - Mathematics and Statistics

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प्रश्न

Find the equation of the tangent to the ellipse 4x2 + 7y2 = 28 from the point (3, –2).

बेरीज
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उत्तर

Given equation of the ellipse is 4x2 + 7y2 = 28

∴ `x^2/7 + y^2/4` = 1

Comparing this equation with `x^2/"a"^2 + y^2/"b"^2` = 1, we get

a2 = 7 and b2 = 4

Equations of tangents to the ellipse

`x^2/"a"^2 + y^2/"b"^2` = 1 having slope m are

y = `"m"x ± sqrt("a"^2"m"^2 + "b"^2)`

Since (3, –2) lies on both the tangents,

–2 = `3"m" ± sqrt(7"m"^2 + 4)`

∴ –2 – 3m = `± sqrt(7"m"^2 + 4)`

Squaring both the sides, we get

9m2 + 12m + 4 = 7m2 + 4

∴ 2m2 + 12m = 0

∴ 2m(m + 6) = 0

∴ m = 0 or m = – 6

∴ These are the slopes of the required tangents.

∴ By slope point form y – y1 = m(x – x1), the equations of the tangents are

y + 2 = 0(x – 3) and y + 2 = –6(x – 3)

∴ y + 2 = 0 and y + 2 = –6x + 18

∴ y + 2 = 0 and 6x + y – 16 = 0.

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Conic Sections - Ellipse
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पाठ 7: Conic Sections - Exercise 7.2 [पृष्ठ १६३]

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बालभारती Mathematics and Statistics 1 (Arts and Science) [English] Standard 11 Maharashtra State Board
पाठ 7 Conic Sections
Exercise 7.2 | Q 11. (ii) | पृष्ठ १६३

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Find the 

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  2. co-ordinates of the focii 
  3. equations of directrices 
  4. length of the latus rectum
  5. distance between focii 
  6. distance between directrices of the ellipse:

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