मराठी

Find Fog And Gof If : F(X) = X2 + 2 , G (X) = 1 − `1/ (1-x)`. - Mathematics

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प्रश्न

Find fog and gof  if : f(x) = `x^2` + 2 , g (x) = 1 − `1/ (1-x)`.

बेरीज
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उत्तर

f (x) = x2+ 2

f : R → [ 2, ∞ )

 g (x) = 1 `- 1/(1-x)`

For domain of g : 1− x ≠ 0 

⇒ x ≠ 1

⇒ Domain of g = R−{1}

g (x )= `1 - 1/(1-x) = (1-x-1)/(1-x) = (-x)/(1-x)`

For range of g :

`y = (- x)/ (1-x)`

⇒ y − xy = − x

⇒ y = xy − x

⇒ y = x (y−1)

⇒ `x = y/(y-1)`

Range of g =R−{1}

So, g : R−{1}→R−{1}

Computing fog : 

Clearly, the range of g is a subset of the domain of f.

⇒ fog : R − {1}→ R

(fog) (x) = f (g (x))

`= f ((-x)/ (x-1) )`

`= ((-x)/ (x-1))^2 + 2`

`=(x^2 + 2x^2 +2-4x)/(1-x)^2`

`= (3x^2-4x +2 )/ (1-x)^2`

Computing gof :

Clearly, the range of f is a subset of the domain of g.

⇒ gof : R→R

(gof) (x) = g (f (x))

= g ( x2 + 2 )

`= 1- 1/(1-(x^2 + 2))`

`= - 1/(1-(x^2 + 2))`

`= (x^2 + 2)/(x^2 + 1)`

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पाठ 2: Functions - Exercise 2.3 [पृष्ठ ५४]

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आरडी शर्मा Mathematics [English] Class 12
पाठ 2 Functions
Exercise 2.3 | Q 1.9 | पृष्ठ ५४

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