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प्रश्न
Find the binding energy of a hydrogen atom in the state n = 2.
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उत्तर
The binding energy (E) of hydrogen atom is given by
`E = (-13.6)/(n^2) eV`
for state n = 2,
`E = -13.6/(2)^2`
`rArr E = -3.4 eV`
Thus, binding energy of hydrogen at n = 2 is - 3.4 eV.
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संबंधित प्रश्न
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