Advertisements
Advertisements
प्रश्न
A hydrogen atom in ground state absorbs 10.2 eV of energy. The orbital angular momentum of the electron is increased by
पर्याय
1.05 × 10−34 J s
2.11 × 10−34 J s
3.16 × 10−34 J s
4.22 × 10−34 J s
Advertisements
उत्तर
1.05 × 10−34 J s
Let after absorption of energy, the hydrogen atom goes to the nth excited state.
Therefore, the energy absorbed can be written as
`10.2 = 13.6 xx (1/1^2 - 1/n^2)`
⇒ `10.2/13.6 = 1- 1/n^2`
`rArr = 1/(n^2) = (13.6 - 10.2)/13.6`
`rArr = 1/n^2 = 3.4/13.6`
`rArr n^2 = 4`
`rArr n = 2`
The orbital angular momentum of the electron in the nth state is given by
`L_n =(nh)/(2pi)`
Change in the angular momentum,
`DeltaL = (2h)/(2pi) - h/(2pi) = h/(2pi)`
`DeltaL = 1.05xx10^-34` Js
APPEARS IN
संबंधित प्रश्न
The first excited energy of a He+ ion is the same as the ground state energy of hydrogen. Is it always true that one of the energies of any hydrogen-like ion will be the same as the ground state energy of a hydrogen atom?
In which of the following transitions will the wavelength be minimum?
As one considers orbits with higher values of n in a hydrogen atom, the electric potential energy of the atom
The radius of the shortest orbit in a one-electron system is 18 pm. It may be
Ionization energy of a hydrogen-like ion A is greater than that of another hydrogen-like ion B. Let r, u, E and L represent the radius of the orbit, speed of the electron, energy of the atom and orbital angular momentum of the electron respectively. In ground state
(a) Find the first excitation potential of He+ ion. (b) Find the ionization potential of Li++ion.
A group of hydrogen atoms are prepared in n = 4 states. List the wavelength that are emitted as the atoms make transitions and return to n = 2 states.
Find the maximum Coulomb force that can act on the electron due to the nucleus in a hydrogen atom.
A hydrogen atom in a state having a binding energy of 0.85 eV makes transition to a state with excitation energy 10.2 e.V (a) Identify the quantum numbers n of the upper and the lower energy states involved in the transition. (b) Find the wavelength of the emitted radiation.
Whenever a photon is emitted by hydrogen in Balmer series, it is followed by another photon in Lyman series. What wavelength does this latter photon correspond to?
A hydrogen atom in state n = 6 makes two successive transitions and reaches the ground state. In the first transition a photon of 1.13 eV is emitted. (a) Find the energy of the photon emitted in the second transition (b) What is the value of n in the intermediate state?
What is the energy of a hydrogen atom in the first excited state if the potential energy is taken to be zero in the ground state?
Find the maximum angular speed of the electron of a hydrogen atom in a stationary orbit.
A hydrogen atom moving at speed υ collides with another hydrogen atom kept at rest. Find the minimum value of υ for which one of the atoms may get ionized.
The mass of a hydrogen atom = 1.67 × 10−27 kg.
The Balmer series for the H-atom can be observed ______.
- if we measure the frequencies of light emitted when an excited atom falls to the ground state.
- if we measure the frequencies of light emitted due to transitions between excited states and the first excited state.
- in any transition in a H-atom.
- as a sequence of frequencies with the higher frequencies getting closely packed.
Let En = `(-1)/(8ε_0^2) (me^4)/(n^2h^2)` be the energy of the nth level of H-atom. If all the H-atoms are in the ground state and radiation of frequency (E2 - E1)/h falls on it ______.
- it will not be absorbed at all.
- some of atoms will move to the first excited state.
- all atoms will be excited to the n = 2 state.
- no atoms will make a transition to the n = 3 state.
A hydrogen atom makes a transition from n = 5 to n = 1 orbit. The wavelength of photon emitted is λ. The wavelength of photon emitted when it makes a transition from n = 5 to n = 2 orbit is ______.
