मराठी
कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

Explain why inspite of nearly the same electronegativity, oxygen forms hydrogen bonding while chlorine does not.

Advertisements
Advertisements

प्रश्न

Explain why inspite of nearly the same electronegativity, oxygen forms hydrogen bonding while chlorine does not.

स्पष्ट करा
Advertisements

उत्तर १

  1. Both nitrogen (N) and chlorine (Cl) have an electronegativity of 3.0.
  2. However, only nitrogen is involved in the hydrogen bonds (e.g., NH3) and not chlorine.
  3. This is due to the smaller atomic size of nitrogen (atomic radius = 70 pm) as compared to chlorine (atomic radius = 99 pm), therefore, N can cause greater polarisation of N-H bond than Cl in the case of Cl-H bond.
  4. Consequently, the N atom is involved in hydrogen bonding and not chlorine.
shaalaa.com

उत्तर २

Despite having almost identical electronegativity values, O and Cl have very different atomic sizes (O = 66 pm, Cl = 99 pm). Because of this, the electron density of the O atom is significantly higher than that of the Cl atom. As a result, although chlorine cannot form hydrogen bonds, oxygen can.

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?

संबंधित प्रश्‍न

Account for the following: Oxygen shows catenation behavior less than sulphur.


Account for the following : There is large difference between the melting and boiling points of oxygen and sulphur.


Give reasons for the following : Oxygen has less electron gain enthalpy with negative sign than sulphur.


List the important sources of sulphur.


Which of the following does not react with oxygen directly?

Zn, Ti, Pt, Fe


Why does NH3 form hydrogen bond but PH3 does not?


The HNH angle value is higher than HPH, HAsH and HSbH angles. Why? [Hint: Can be explained on the basis of sp3 hybridisation in NH3 and only s−p bonding between hydrogen and other elements of the group].


Knowing the electron gain enthalpy values for \[\ce{O -> O-}\] and \[\ce{O -> O^{2-}}\] as −141 and 702 kJ mol−1 respectively, how can you account for the formation of a large number of oxides having O2− species and not O?

(Hint: Consider lattice energy factor in the formation of compounds).


Draw the structures of `H_3PO_2`

 


Give a reason for the following:

Fluorine gives only one oxide but chlorine gives a series of oxides.


Arrange the following in order of the property indicated set.
HF, HCl, HBr, HI - decreasing bond enthalpy.


The formation of \[\ce{O^+_2[PtF6]^-}\] is the basis for the formation of first xenon compound. This is because ____________.


Given below are two statements labelled as Assertion (A) and Reason (R).

Assertion (A): Electron gain enthalpy of oxygen is less than that of Flourine but greater than Nitrogen.

Reason (R): Ionisation enthalpies of the elements follow the order Nitrogen > Oxygen > Fluorine.

Select the most appropriate answer from the options given below:


Write a balanced chemical equation for the reaction showing catalytic oxidation of NH3 by atmospheric oxygen.


In forming (i) \[\ce{N2 -> N^{+}2}\] and (ii) \[\ce{O2 -> O^{+}2}\]; the electrons respectively are removed from:


Which of the following compound is a peroxide?


What is the basicity of \[\ce{H3PO4}\]?


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×