मराठी
कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

Strong reducing behaviour of HX3POX2 is due to ______.

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प्रश्न

Strong reducing behaviour of \[\ce{H3PO2}\] is due to ______.

पर्याय

  • Low oxidation state of phosphorus

  • Presence of two –OH groups and one P–H bond

  • Presence of one –OH group and two P–H bonds

  • High electron gain enthalpy of phosphorus

MCQ
रिकाम्या जागा भरा
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उत्तर

Strong reducing behaviour of \[\ce{H3PO2}\] is due to presence of one –OH group and two P–H bonds.

Explanation:

\[\ce{H3PO2}\] has one O – H group and two P – H bonds.

The existence of a P – H link gives phosphorus oxyacids their reducing characteristics. It has a strong proclivity for releasing protons. As a result, it demonstrates a decreasing nature.

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  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 7: The p-block Elements - Multiple Choice Questions (Type - I) [पृष्ठ ९१]

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एनसीईआरटी एक्झांप्लर Chemistry Exemplar [English] Class 12
पाठ 7 The p-block Elements
Multiple Choice Questions (Type - I) | Q 10 | पृष्ठ ९१

संबंधित प्रश्‍न

Give reasons: SO2 is reducing while TeO2 is an oxidising agent.


Account for the following : There is large difference between the melting and boiling points of oxygen and sulphur.


Give reasons for the following : H2Te is the strongest reducing agent amongst all the hydrides of Group 16 elements.


List the important sources of sulphur.


Why does NH3 form hydrogen bond but PH3 does not?


Justify the placement of O, S, Se, Te and Po in the same group of the periodic table in terms of electronic configuration, oxidation state and hydride formation.


Knowing the electron gain enthalpy values for \[\ce{O -> O-}\] and \[\ce{O -> O^{2-}}\] as −141 and 702 kJ mol−1 respectively, how can you account for the formation of a large number of oxides having O2− species and not O?

(Hint: Consider lattice energy factor in the formation of compounds).


Arrange the following in the order of property indicated for the given set:

F2, Cl2, Br2, I2 - increasing bond dissociation enthalpy.


Arrange the following in the order of the property indicated against set :
H2O, H2S, H2Se, H2Te − increasing acidic character.


Explain the following properties of group 16 elements :
1) Electro negativity
2) Melting and boiling points
3) Metallic character
4) Allotropy


 Give reactions for the following: 
O – O single bond is weaker than S – S single bond. 


Arrange the following in order of the property indicated set.
HF, HCl, HBr, HI - decreasing bond enthalpy.


Given below are two statements labelled as Assertion (A) and Reason (R).

Assertion (A): Electron gain enthalpy of oxygen is less than that of Flourine but greater than Nitrogen.

Reason (R): Ionisation enthalpies of the elements follow the order Nitrogen > Oxygen > Fluorine.

Select the most appropriate answer from the options given below:


Out of \[\ce{H2O}\] and \[\ce{H2S}\], which one has higher bond angle and why?


In forming (i) \[\ce{N2 -> N^{+}2}\] and (ii) \[\ce{O2 -> O^{+}2}\]; the electrons respectively are removed from:


The correct order of ΔiHs among the following elements is


These are physical properties of an elements.

  1. Sublimation enthalpy
  2. Ionisation enthalpy
  3. Hydration enthalpy
  4. Electron gain enthalpy

The total number of above properties that affect the reduction potential is ______. (Integer answer)


______ is a radioactive element in group 16 elements.


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