मराठी

Give reasons: SO2 is reducing while TeO2 is an oxidising agent.

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प्रश्न

Give reasons: SO2 is reducing while TeO2 is an oxidising agent.

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उत्तर

In case of sulphur, because of the presence of empty d-orbital, it can expand its oxidation state from the + 4 to the +6 oxidation state. Hence, it acts as a reducing agent.

Te is a heavy element and so because of the inert pair effect, the lower oxidation state is more stable. Hence, it acts as an oxidising agent.

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2015-2016 (March) All India Set 2 C

व्हिडिओ ट्यूटोरियलVIEW ALL [2]

संबंधित प्रश्‍न

a. Explain the trends in the following properties with reference to group 16:

1 Atomic radii and ionic radii

2 Density

3 ionisation enthalpy

4 Electronegativity

b. In the electolysis of AgNO3 solution 0.7g of Ag is deposited after a certain period of time. Calulate the quantity of electricity required in coulomb. (Molar mass of Ag is 107.9g mol-1)

 


Account for the following : There is large difference between the melting and boiling points of oxygen and sulphur.


Which of the following does not react with oxygen directly?

Zn, Ti, Pt, Fe


Why are halogens strong oxidising agents?


Explain why inspite of nearly the same electronegativity, oxygen forms hydrogen bonding while chlorine does not.


Strong reducing behaviour of \[\ce{H3PO2}\] is due to ______.


Which of the following statements are correct?

(i) \[\ce{CaF2 + H2SO4 -> CaSO4 + 2HF}\]

(ii) \[\ce{2HI + H2SO4 -> I2 + SO2 + 2H2O}\]

(iii) \[\ce{Cu + 2H2SO4 -> CuSO4 + SO2 + 2H2O}\]

(iv) \[\ce{Nacl + H2SO4 -> NaHSO4 + HCl}\]


The correct order of ΔiHs among the following elements is


These are physical properties of an elements.

  1. Sublimation enthalpy
  2. Ionisation enthalpy
  3. Hydration enthalpy
  4. Electron gain enthalpy

The total number of above properties that affect the reduction potential is ______. (Integer answer)


Given below are two statements:

Statement I: The boiling point of hydrides of Group 16 elements follows the order:

H2O > H2Te > H2Se > H2S

Statement II: On the basis of molecular mass, H2O is expected to have a lower boiling point than the other members of the group but due to the presence of extensive H-bonding in H2O, it has a higher boiling point.

In the light of the above statements, choose the correct answer from the options given below:


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