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प्रश्न
Give reasons: SO2 is reducing while TeO2 is an oxidising agent.
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उत्तर
In case of sulphur, because of the presence of empty d-orbital, it can expand its oxidation state from the + 4 to the +6 oxidation state. Hence, it acts as a reducing agent.
Te is a heavy element and so because of the inert pair effect, the lower oxidation state is more stable. Hence, it acts as an oxidising agent.
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संबंधित प्रश्न
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1 Atomic radii and ionic radii
2 Density
3 ionisation enthalpy
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(iii) \[\ce{Cu + 2H2SO4 -> CuSO4 + SO2 + 2H2O}\]
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