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कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

Which of the following statements are correct? (i) CaFX2+HX2SOX4⟶CaSOX4+2HF (ii) 2HI+HX2SOX4⟶IX2+SOX2+2HX2O (iii) Cu+2HX2SOX4⟶CuSOX4+SOX2+2HX2O (iv) Nacl+HX2SOX4⟶NaHSOX4+HCl

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प्रश्न

Which of the following statements are correct?

(i) \[\ce{CaF2 + H2SO4 -> CaSO4 + 2HF}\]

(ii) \[\ce{2HI + H2SO4 -> I2 + SO2 + 2H2O}\]

(iii) \[\ce{Cu + 2H2SO4 -> CuSO4 + SO2 + 2H2O}\]

(iv) \[\ce{Nacl + H2SO4 -> NaHSO4 + HCl}\]

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उत्तर

(ii) \[\ce{2HI + H2SO4 -> I2 + SO2 + 2H2O}\]

(iii) \[\ce{Cu + 2H2SO4 -> CuSO4 + SO2 + 2H2O}\]

Explanation:

\[\begin{array}{cc}
\ce{\underset{-2}{O}}\phantom{......}\\
||\phantom{.....}\\
\ce{\overset{-1}{HO} - S - \overset{-1}{O} - OH}\\
||\phantom{.....}\\
\ce{\overset{-2}{O}}\phantom{.....}\\
\end{array}\]

\[\begin{array}{cc}
\phantom{.}\ce{O}\phantom{.......}\ce{O}\phantom{.....}\\
\phantom{.}||\phantom{........}||\phantom{.....}\\
\ce{HO - S - O - O - S - OH}\\
\phantom{.}||\phantom{........}||\phantom{.....}\\
\phantom{.}\ce{O}\phantom{........}\ce{O}\phantom{.....}
\end{array}\]

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अध्याय 7: The p-block Elements - Multiple Choice Questions (Type - I) [पृष्ठ ९६]

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एनसीईआरटी एक्झांप्लर Chemistry Exemplar [English] Class 12
अध्याय 7 The p-block Elements
Multiple Choice Questions (Type - I) | Q 36 | पृष्ठ ९६

संबंधित प्रश्न

a. Explain the trends in the following properties with reference to group 16:

1 Atomic radii and ionic radii

2 Density

3 ionisation enthalpy

4 Electronegativity

b. In the electolysis of AgNO3 solution 0.7g of Ag is deposited after a certain period of time. Calulate the quantity of electricity required in coulomb. (Molar mass of Ag is 107.9g mol-1)

 


Give reasons: SO2 is reducing while TeO2 is an oxidising agent.


Write the order of thermal stability of the hydrides of Group 16 elements.


The HNH angle value is higher than HPH, HAsH and HSbH angles. Why? [Hint: Can be explained on the basis of sp3 hybridisation in NH3 and only s−p bonding between hydrogen and other elements of the group].


Justify the placement of O, S, Se, Te and Po in the same group of the periodic table in terms of electronic configuration, oxidation state and hydride formation.


Knowing the electron gain enthalpy values for \[\ce{O -> O-}\] and \[\ce{O -> O^{2-}}\] as −141 and 702 kJ mol−1 respectively, how can you account for the formation of a large number of oxides having O2− species and not O?

(Hint: Consider lattice energy factor in the formation of compounds).


Give reasons Thermal stability decreases from H2O to H2Te.


Arrange the following in the order of the property indicated against set :
H2O, H2S, H2Se, H2Te − increasing acidic character.


Explain the following properties of group 16 elements :
1) Electro negativity
2) Melting and boiling points
3) Metallic character
4) Allotropy


Give a reason for the following:

Fluorine gives only one oxide but chlorine gives a series of oxides.


Arrange the following in order of the property indicated set.
HF, HCl, HBr, HI - decreasing bond enthalpy.


Given below are two statements labelled as Assertion (A) and Reason (R).

Assertion (A): Electron gain enthalpy of oxygen is less than that of Flourine but greater than Nitrogen.

Reason (R): Ionisation enthalpies of the elements follow the order Nitrogen > Oxygen > Fluorine.

Select the most appropriate answer from the options given below:


Strong reducing behaviour of \[\ce{H3PO2}\] is due to ______.


Write a balanced chemical equation for the reaction showing catalytic oxidation of NH3 by atmospheric oxygen.


Out of \[\ce{H2O}\] and \[\ce{H2S}\], which one has higher bond angle and why?


Which of the following compound is a peroxide?


What is the basicity of \[\ce{H3PO4}\]?


______ is a gaseous element of group 16.


Given below are two statements:

Statement I: The boiling point of hydrides of Group 16 elements follows the order:

H2O > H2Te > H2Se > H2S

Statement II: On the basis of molecular mass, H2O is expected to have a lower boiling point than the other members of the group but due to the presence of extensive H-bonding in H2O, it has a higher boiling point.

In the light of the above statements, choose the correct answer from the options given below:


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