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कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

Which of the following statements are correct? (i) CaFX2+HX2SOX4⟶CaSOX4+2HF (ii) 2HI+HX2SOX4⟶IX2+SOX2+2HX2O (iii) Cu+2HX2SOX4⟶CuSOX4+SOX2+2HX2O (iv) Nacl+HX2SOX4⟶NaHSOX4+HCl - Chemistry

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प्रश्न

Which of the following statements are correct?

(i) \[\ce{CaF2 + H2SO4 -> CaSO4 + 2HF}\]

(ii) \[\ce{2HI + H2SO4 -> I2 + SO2 + 2H2O}\]

(iii) \[\ce{Cu + 2H2SO4 -> CuSO4 + SO2 + 2H2O}\]

(iv) \[\ce{Nacl + H2SO4 -> NaHSO4 + HCl}\]

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उत्तर

(ii) \[\ce{2HI + H2SO4 -> I2 + SO2 + 2H2O}\]

(iii) \[\ce{Cu + 2H2SO4 -> CuSO4 + SO2 + 2H2O}\]

Explanation:

\[\begin{array}{cc}
\ce{\underset{-2}{O}}\phantom{......}\\
||\phantom{.....}\\
\ce{\overset{-1}{HO} - S - \overset{-1}{O} - OH}\\
||\phantom{.....}\\
\ce{\overset{-2}{O}}\phantom{.....}\\
\end{array}\]

\[\begin{array}{cc}
\phantom{.}\ce{O}\phantom{.......}\ce{O}\phantom{.....}\\
\phantom{.}||\phantom{........}||\phantom{.....}\\
\ce{HO - S - O - O - S - OH}\\
\phantom{.}||\phantom{........}||\phantom{.....}\\
\phantom{.}\ce{O}\phantom{........}\ce{O}\phantom{.....}
\end{array}\]

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पाठ 7: The p-block Elements - Multiple Choice Questions (Type - I) [पृष्ठ ९६]

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एनसीईआरटी एक्झांप्लर Chemistry [English] Class 12
पाठ 7 The p-block Elements
Multiple Choice Questions (Type - I) | Q 36 | पृष्ठ ९६

संबंधित प्रश्‍न

Account for the following : There is large difference between the melting and boiling points of oxygen and sulphur.


Give reasons for the following : H2Te is the strongest reducing agent amongst all the hydrides of Group 16 elements.


Write the order of thermal stability of the hydrides of Group 16 elements.


Which of the following does not react with oxygen directly?

Zn, Ti, Pt, Fe


Knowing the electron gain enthalpy values for \[\ce{O -> O-}\] and \[\ce{O -> O^{2-}}\] as −141 and 702 kJ mol−1 respectively, how can you account for the formation of a large number of oxides having O2− species and not O?

(Hint: Consider lattice energy factor in the formation of compounds).


Give reasons Thermal stability decreases from H2O to H2Te.


Draw the structures of `H_3PO_2`

 


Explain the following properties of group 16 elements :
1) Electro negativity
2) Melting and boiling points
3) Metallic character
4) Allotropy


 Give reactions for the following: 
O – O single bond is weaker than S – S single bond. 


Give a reason for the following:

Fluorine gives only one oxide but chlorine gives a series of oxides.


The boiling points of hydrides of group 16 are in the order:


The formation of \[\ce{O^+_2[PtF6]^-}\] is the basis for the formation of first xenon compound. This is because ____________.


Given below are two statements labelled as Assertion (A) and Reason (R).

Assertion (A): Electron gain enthalpy of oxygen is less than that of Flourine but greater than Nitrogen.

Reason (R): Ionisation enthalpies of the elements follow the order Nitrogen > Oxygen > Fluorine.

Select the most appropriate answer from the options given below:


Strong reducing behaviour of \[\ce{H3PO2}\] is due to ______.


Out of \[\ce{H2O}\] and \[\ce{H2S}\], which one has higher bond angle and why?


The correct order of ΔiHs among the following elements is


What is the basicity of \[\ce{H3PO4}\]?


______ is a radioactive element in group 16 elements.


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