हिंदी
कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

Explain why inspite of nearly the same electronegativity, oxygen forms hydrogen bonding while chlorine does not.

Advertisements
Advertisements

प्रश्न

Explain why inspite of nearly the same electronegativity, oxygen forms hydrogen bonding while chlorine does not.

स्पष्ट कीजिए
Advertisements

उत्तर १

  1. Both nitrogen (N) and chlorine (Cl) have an electronegativity of 3.0.
  2. However, only nitrogen is involved in the hydrogen bonds (e.g., NH3) and not chlorine.
  3. This is due to the smaller atomic size of nitrogen (atomic radius = 70 pm) as compared to chlorine (atomic radius = 99 pm), therefore, N can cause greater polarisation of N-H bond than Cl in the case of Cl-H bond.
  4. Consequently, the N atom is involved in hydrogen bonding and not chlorine.
shaalaa.com

उत्तर २

Despite having almost identical electronegativity values, O and Cl have very different atomic sizes (O = 66 pm, Cl = 99 pm). Because of this, the electron density of the O atom is significantly higher than that of the Cl atom. As a result, although chlorine cannot form hydrogen bonds, oxygen can.

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?

संबंधित प्रश्न

Give reasons for the following : H2Te is the strongest reducing agent amongst all the hydrides of Group 16 elements.


Give reasons for the following : Oxygen has less electron gain enthalpy with negative sign than sulphur.


Write the order of thermal stability of the hydrides of Group 16 elements.


The HNH angle value is higher than HPH, HAsH and HSbH angles. Why? [Hint: Can be explained on the basis of sp3 hybridisation in NH3 and only s−p bonding between hydrogen and other elements of the group].


Knowing the electron gain enthalpy values for \[\ce{O -> O-}\] and \[\ce{O -> O^{2-}}\] as −141 and 702 kJ mol−1 respectively, how can you account for the formation of a large number of oxides having O2− species and not O?

(Hint: Consider lattice energy factor in the formation of compounds).


Explain the following properties of group 16 elements :
1) Electro negativity
2) Melting and boiling points
3) Metallic character
4) Allotropy


Arrange the following in order of the property indicated set.
HF, HCl, HBr, HI - decreasing bond enthalpy.


The boiling points of hydrides of group 16 are in the order:


Which of the following statement is incorrect?


Match the items of Columns I and II and mark the correct option.

Column I Column II
(A) \[\ce{H2SO4}\] (1) Highest electron gain enthalpy
(B) \[\ce{CCl3NO2}\] (2) Chalcogen
(C) \[\ce{Cl2}\] (3) Tear gas
(D) Sulphur (4) Storage batteries

Given below are two statements labelled as Assertion (A) and Reason (R).

Assertion (A): Electron gain enthalpy of oxygen is less than that of Flourine but greater than Nitrogen.

Reason (R): Ionisation enthalpies of the elements follow the order Nitrogen > Oxygen > Fluorine.

Select the most appropriate answer from the options given below:


Which of the following statements are correct?

(i) \[\ce{CaF2 + H2SO4 -> CaSO4 + 2HF}\]

(ii) \[\ce{2HI + H2SO4 -> I2 + SO2 + 2H2O}\]

(iii) \[\ce{Cu + 2H2SO4 -> CuSO4 + SO2 + 2H2O}\]

(iv) \[\ce{Nacl + H2SO4 -> NaHSO4 + HCl}\]


Write a balanced chemical equation for the reaction showing catalytic oxidation of NH3 by atmospheric oxygen.


Which of the following compound is a peroxide?


What is the basicity of \[\ce{H3PO4}\]?


______ is a radioactive element in group 16 elements.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×