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प्रश्न
Define carbohydrates.
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उत्तर
Carbohydrates are optically active polyhydroxy aldehydes or polyhydroxy ketones or compounds that can be hydrolysed to polyhydroxy aldehydes or polyhydroxy ketones.
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संबंधित प्रश्न
Give scientific reasons:
Hydrolysis of sucrose is called inversion.
Write the name of the polysaccharide used for the commercial preparation of glucose.
Draw the structure of α-D glucopyranose.
Explain the preparation of glucose from sucrose.
What is the action of the following reagents on glucose?
hydroxylamine
Identify the given structure 'P' and 'Q'.
Identify the substances having glycosidic bond and peptide bond, respectively in their structure:
Which of the following carbohydrate is sweet to taste?
From the following which is a heteropolysaccharide?
______ is the prosthetic group of glycoproteins.
The reserve food material in animals is ____________.
The number of asymmetric carbon atoms in the glucose molecule is ____________.
Match the columns and select the correct option.
| Column I | Column II | ||
| i. | Starch | a. | Animal storage molecule |
| ii. | Cellulose | b. | Plant storage molecule |
| iii. | Glycogen | c. | Heparin |
| iv. | Heteropolysaccharide | d. | Plant cell wall component |
On hydrolysis sucrose gives ____________.
What is the quantity of glucose obtained when 68.4 g of sucrose is hydrolyzed in laboratory under ideal condition?
(Molar mass of sucrose = 342 g mol−1)
Identify the product Y in the following reaction.
\[\ce{Maltose ->[Hydrolysis] X ->[dil. HNO3][(excess)] Y}\]
How many optical isomers are possible for a compound having four asymmetric carbon atoms?
Glucose on oxidation with bromine water yields gluconic acid. This reaction confirms the presence of ______.
The two monosaccharides in a disaccharide are held together by ______ bonds.
Which carbon atoms of fructose are bonded together through oxygen forming fructofuranose?
Identify the monosaccharide containing only one asymmetric carbon atom in its molecule.
Corn is immersed in boiling water. It is then cooled, and the solution becomes sweet. It is due to ______.
\[\ce{CH2OH - CO - (CHOH)4 - CH2OH}\] is an example of ______.
Why carbohydrates are generally optically active.
Why carbohydrates are generally optically active.
CH2 OH - CO - (CHOH)4 - CH2 OH is an example of ______.
Why carbohydrates are generally optically active?
\[\ce{CH2OH - CO - (CHOH)4 - CH2OH}\] is an example of ______.
Why carbohydrates are generally optically active.
