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प्रश्न
C–Cl bond length in chlorobenzene is shorter than C–Cl bond length in CH3–Cl.
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उत्तर
In chlorobenzene, the C−Cl bond gets partial double bond character because of the +M effect shown by the Cl group. Due to double bond character, the bond length decreases in chlorobenzene as compared to the normal CH3−Cl bond length. Therefore, the C–Cl bond length in chlorobenzene is shorter than the C–Cl bond length in CH3–Cl.
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संबंधित प्रश्न
Which would undergo SN1 reaction faster in the following pair and why?
Arrange the compounds of the following set in order of reactivity towards SN2 displacement:
1-Bromo-3-methylbutane, 2-Bromo-2-methylbutane, 2-Bromo-3-methylbutane
In the reaction, \[\ce{R - X + NaOR' -> ROR’ + X}\] ( – ve ion). The main product formed is:
Halogenation of alkanes is ____________.
Tertiary alkyl halides are practically inert to substitution by SN2 mechanism because of ____________.
2-Bromopentane is heated with potassium ethoxide in ethanol. The major product obtained is ____________.
How do polar solvents help in the first step in SN1 mechanism?
Among the following compounds I - IV, which one forms a yellow precipitate on reacting sequentially with (i) NaOH (ii) dil. HNO3 (iii) AgNO3?
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| I | II | III | IV |
Explain why Grignard reagents should be prepared under anhydrous conditions.
Which alkyl halide from the following pair would you expect to react more rapidly by an SN2 mechanism? Explain your answer.
\[\begin{array}{cc}\ce{CH3CH2CHCH3}\\\phantom{...}|\\\phantom{....}\ce{Br}\end{array}\] or \[\begin{array}{cc}\phantom{.....}\ce{CH3}\\\phantom{..}|\\\ce{H3C - C - Br}\\\phantom{..}|\\\phantom{....}\ce{CH3}\end{array}\]
