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प्रश्न
C–Cl bond length in chlorobenzene is shorter than C–Cl bond length in CH3–Cl.
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उत्तर
In chlorobenzene, the C−Cl bond gets partial double bond character because of the +M effect shown by the Cl group. Due to double bond character, the bond length decreases in chlorobenzene as compared to the normal CH3−Cl bond length. Therefore, the C–Cl bond length in chlorobenzene is shorter than the C–Cl bond length in CH3–Cl.
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संबंधित प्रश्न
How do you convert the following:
Ethanol to propanenitrile
Out of 
, which is more reactive towards SN1 reaction and why?
Given reasons: SN1 reactions are accompanied by racemization in optically active alkyl halides.
Optically active isomers but not mirror images are called ____________.
Tertiary alkyl halides are practically inert to substitution by SN2 mechanism because of ____________.
An organic molecule necessarily shows optical activity if it ____________.
Which of the statements are correct about above reaction?
(i) (a) and (e) both are nucleophiles.
(ii) In (c) carbon atom is sp3 hybridised.
(iii) In (c) carbon atom is sp2 hybridised.
(iv) (a) and (e) both are electrophiles.
Give reason for the following:
The product formed during SN1 reaction is a racemic mixture.
Which alkyl halide from the following pair would you expect to react more rapidly by an SN2 mechanism? Explain your answer.
\[\begin{array}{cc}\ce{CH3CH2CHCH3}\\
\phantom{.....}|\\
\phantom{......}\ce{Br}\\
\end{array}\] or \[\begin{array}{cc}\phantom{.......}\ce{CH3}\\
\phantom{...}|\\
\ce{H3C - C - Br}\\
\phantom{...}|\\
\phantom{.......}\ce{CH3}\\
\end{array}\]
Consider the reactions,
(i) \[\begin{array}{cc}
\phantom{}\ce{\underset{}{(CH3)2CH - CH2Br} ->[C2H5OH] \underset{}{(CH3)2CH - CH2OC2H5 + HBr}}\\
\end{array}\]
(ii) \[\begin{array}{cc}
\phantom{}\ce{\underset{}{(CH3)2CH - CH2Br} ->[C2H5O-] \underset{}{(CH3)2CH - CH2OC2H5 + Br-}}\\
\end{array}\]
The mechanisms of reactions (i) and (ii) are respectively:
