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प्रश्न
Answer the following in one or two sentences.
A solution concentration is expressed in molarity and not in molality while considering osmotic pressure. Why?
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उत्तर
- Fraction `n/v` corresponds to the molarity (M) of a solution of a non-dissociating or totally dissociating solute `pi = n/v RT`
- Osmotic pressure increases by `1/273` for each degree of temperature increase.
- But osmotic pressure measurements are made at specific constant temperatures. In this case, M remains constant.
`M = n_2/V` [Temp. dependent]
`m = n_2/W_1` [Temp. independent]
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संबंधित प्रश्न
Determine the osmotic pressure of a solution prepared by dissolving 2.5 × 10−2 g of K2SO4 in 2L of water at 25°C, assuming that it is completely dissociated.
(R = 0.0821 L atm K−1 mol−1, Molar mass of K2SO4 = 174 g mol−1)
Which of the following is not a colligative property?
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Calculate the osmotic pressure in pascals exerted by a solution prepared by dissolving 1.0 g of polymer of molar mass 185,000 in 450 mL of water at 37°C.
At 300 K, 36 g of glucose present in a litre of its solution has an osmotic pressure of 4.98 bar. If the osmotic pressure of the solution is 1.52 bars at the same temperature, what would be its concentration?
Determine the amount of CaCl2 (i = 2.47) dissolved in 2.5 litre of water such that its osmotic pressure is 0.75 atm at 27°C.
Determine the osmotic pressure of a solution prepared by dissolving 25 mg of K2SO4 in 2 liter of water at 25°C, assuming that it is completely dissociated.
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Calculate the mass of a compound (molar mass = 256 g mol−1) to be dissolved in 75 g of benzene to lower its freezing point by 0.48 K (Kf = 5.12 K kg mol−1).
Define the following term:
isotonic solution
Choose the most correct option.
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A living cell contains a solution which is isotonic with 0.3 M sugar solution. What osmotic pressure develops when the cell is placed in 0.1 M KCl solution at body temperature?
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Answer the following.
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Assertion (A) : Osmotic pressure is a colligative property.
Reason (R) : Osmotic pressure is proportional to the molality.
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(R = 0.082 L atm K−1 mol, Molar mass K2SO4 = 174 g mol−1)
Prove that: M2 = `(W_2RT)/(πV)`.
Define reverse osmosis.
How will you determine molar mass of solute from osmotic pressure?
