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प्रश्न
A random survey of the number of children of various age groups playing in a park was found as follows:
| Age (in years) | Number of children |
| 1 - 2 | 5 |
| 2 - 3 | 3 |
| 3 - 5 | 6 |
| 5 - 7 | 12 |
| 7 - 10 | 9 |
| 10 - 15 | 10 |
| 15 - 17 | 4 |
Draw a histogram to represent the data above.
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उत्तर
Here, it can be observed that the data has class intervals of varying width. The proportion of children per 1 year interval can be calculated as follows.
| Age (in years) | Frequency (Number of children) | Width of the class | Length of the rectangle |
| 1 - 2 | 5 | 1 | `(5 xx 1)/1` = 5 |
| 2 - 3 | 3 | 1 | `(3 xx 1)/1` = 3 |
| 3 - 5 | 6 | 2 | `(6 xx 1)/2` = 3 |
| 5 - 7 | 12 | 2 | `(12 xx 1)/2` = 6 |
| 7 - 10 | 9 | 3 | `(9 xx 1)/3` = 6 |
| 10 - 15 | 10 | 5 | `(10 xx 1)/5` = 2 |
| 15 - 17 | 4 | 2 | `(4 xx 1)/2` = 2 |
Taking the age of children on the x-axis and the proportion of children per 1 year interval on the y-axis, the histogram can be drawn as follows:
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Read the following bar graph (Fig. 23.12) and answer the following questions:
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(iii)In which year the import is maximum?
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| Year | 1992 | 1993 | 1994 | 1995 | 1996 |
| Loan (in crores of rupees) |
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| Height (in cm): | 124 to 128 |
128 to 132 |
132 to 136 |
136 to 140 |
140 to 144 |
144 to 148 |
148 to 152 |
152 to 156 |
156 to 160 |
160 to 164 |
| No. of Children: | 5 | 8 | 17 | 24 | 16 | 12 | 6 | 4 | 3 | 1 |
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Draw a histogram to represent the following grouped frequency distribution:
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| 20 – 24 | 10 |
| 25 – 29 | 28 |
| 30 – 34 | 32 |
| 35 – 39 | 48 |
| 40 – 44 | 50 |
| 45 – 49 | 35 |
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| 10 – 20 | 6 |
| 20 – 30 | 17 |
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Construct a histogram to represent the data above.
