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प्रश्न
A cylinder containing one gram molecule of the gas was compressed adiabatically until its temperature rose from 27°C to 97°C. Calculate the work done and heat produced in the gas (𝛾 = 1.5).
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उत्तर
T1 = 27° C = 273 + 27 = 300 K
When gas is compressed adiabatically, work done on the gas is given by
`W = R/(1-γ) (T_2 - T_1) = (8.3xx(370-300))/(1-1.5)`
or W = −11.62 × (102 J)
Heat produced,
`H = W/J = (11.62xx10^2)/4.2`
= 276.7 cal
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