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महाराष्ट्र राज्य शिक्षण मंडळएचएससी वाणिज्य (इंग्रजी माध्यम) इयत्ता १२ वी

A company decides to set aside a certain sum at the end of each year to create a sinking fund, which should amount to ₹ 4 lakhs in 4 years at 10% p.a. Find the amount to be set aside each year? [Give - Mathematics and Statistics

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प्रश्न

A company decides to set aside a certain sum at the end of each year to create a sinking fund, which should amount to ₹ 4 lakhs in 4 years at 10% p.a. Find the amount to be set aside each year?
[Given (1.1)4 = 1.4641]

बेरीज
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उत्तर

Given, A = ₹ 4,00,000, n = 4 years, r = 10% p.a, i = `"r"/100 = 10/100` = 0.1

Now, A = `"C"/"i"[(1 + "i")^"n" - 1]`

∴ 4,00,000 = `"C"/0.1[(1 + 0.1)^4 - 1]`

∴ 4,00,000 × 0.1 = C[(1.1)4 − 1]

∴ 40,000 = C[1.4641 − 1]

∴ 40,000 = C(0.4641)

∴ C = `(40,000)/0.4641`

∴ C = ₹ 86,188.32

∴ The amount to be set aside each year is ₹ 2,00,000.

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Annuity
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 2.2: Insurance and Annuity - Q.4

संबंधित प्रश्‍न

Find accumulated value after 1 year of an annuity immediate in which ₹ 10,000 is invested every quarter at 16% p.a. compounded quarterly. [Given (1.04)4 = 1.1699]


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A person sets up a sinking fund in order to have ₹ 1,00,000 after 10 years. What amount should be deposited bi-annually in the account that pays him 5% p.a. compounded semi-annually? [Given (1.025)20 = 1.675]


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If payments of an annuity fall due at the end of every period, the series is called annuity __________.


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The future value of an annuity is the accumulated values of all installments.


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Find the rate of interest compounded annually if an ordinary annuity of ₹20,000 per year amounts to ₹41,000 in 2 years.


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Find the present value of an annuity immediate of ₹20,000 per annum for 3 years at 10% p.a. compounded annually. [(1.1)–3 = 0.7513]


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For annuity due,

C = ₹ 20,000, n = 3, I = 0.1, (1.1)–3 = 0.7513

Therefore, P = `square/0.1 xx [1 - (1 + 0.1)^square]`

= 2,00,000 [1 – 0.7513]

= ₹ `square`


The future amount, A = ₹ 10,00,000

Period, n = 20, r = 5%, (1.025)20 = 1.675

A = `"C"/"I" [(1 + "i")^"n" - 1]`

I = `5/200` = `square` as interest is calculated semi-annually

A = 10,00,000 = `"C"/"I" [(1 + "i")^"n" - 1]`

10,00,000 = `"C"/0.025 [(1 + 0.025)^square - 1]`

= `"C"/0.025 [1.675 - 1]`

10,00,000 = `("C" xx 0.675)/0.025`

C = ₹ `square`


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