Advertisements
Advertisements
प्रश्न
A company decides to set aside a certain sum at the end of each year to create a sinking fund, which should amount to ₹ 4 lakhs in 4 years at 10% p.a. Find the amount to be set aside each year?
[Given (1.1)4 = 1.4641]
Advertisements
उत्तर
Given, A = ₹ 4,00,000, n = 4 years, r = 10% p.a, i = `"r"/100 = 10/100` = 0.1
Now, A = `"C"/"i"[(1 + "i")^"n" - 1]`
∴ 4,00,000 = `"C"/0.1[(1 + 0.1)^4 - 1]`
∴ 4,00,000 × 0.1 = C[(1.1)4 − 1]
∴ 40,000 = C[1.4641 − 1]
∴ 40,000 = C(0.4641)
∴ C = `(40,000)/0.4641`
∴ C = ₹ 86,188.32
∴ The amount to be set aside each year is ₹ 2,00,000.
APPEARS IN
संबंधित प्रश्न
Find the accumulated (future) value of annuity of ₹ 800 for 3 years at interest rate 8% compounded annually. [Given (1.08)3 = 1.2597]
Find accumulated value after 1 year of an annuity immediate in which ₹ 10,000 is invested every quarter at 16% p.a. compounded quarterly. [Given (1.04)4 = 1.1699]
A person plans to put ₹400 at the beginning of each year for 2 years in a deposit that gives interest at 2% p.a. compounded annually. Find the amount that will be accumulated at the end of 2 years.
A person sets up a sinking fund in order to have ₹ 1,00,000 after 10 years. What amount should be deposited bi-annually in the account that pays him 5% p.a. compounded semi-annually? [Given (1.025)20 = 1.675]
In an ordinary annuity, payments or receipts occur at ______.
______ is a series of constant cash flows over a limited period of time.
Fill in the blank :
The person who receives annuity is called __________.
Fill in the blank :
An annuity where payments continue forever is called __________.
Fill in the blank :
If payments of an annuity fall due at the end of every period, the series is called annuity __________.
State whether the following is True or False :
Payment of every annuity is called an installment.
State whether the following is True or False :
The present value of an annuity is the sum of the present value of all installments.
State whether the following is True or False :
The future value of an annuity is the accumulated values of all installments.
Solve the following :
Find the rate of interest compounded annually if an ordinary annuity of ₹20,000 per year amounts to ₹41,000 in 2 years.
Solve the following :
A man borrowed some money and paid back in 3 equal installments of ₹2,160 each. What amount did he borrow if the rate of interest was 20% per annum compounded annually? Also find the total interest charged. [(1.2)3 = 0.5787]
Solve the following :
Find the future value after 2 years if an amount of ₹12,000 is invested at the end of every half year at 12% p. a. compounded half yearly. [(1.06)4 = 1.2625]
Solve the following :
After how many years would an annuity due of ₹3,000 p.a. accumulated ₹19,324.80 at 20% p. a. compounded yearly? [Given (1.2)4 = 2.0736]
Multiple choice questions:
Rental payment for an apartment is an example of ______
Multiple choice questions:
In annuity calculations, the interest is usually taken as ______
Multiple choice questions:
The present value of an immediate annuity of ₹ 10,000 paid each quarter for four quarters at 16% p.a. compounded quarterly is ______
State whether the following statement is True or False:
A sinking fund is a fund established by financial organization
State whether the following statement is True or False:
The future value of an annuity is the accumulated values of all instalments
State whether the following statement is True or False:
An annuity where payments continue forever is called perpetuity
The present value of an immediate annuity for 4 years at 10% p.a. compounded annually is ₹ 23,400. It’s accumulated value after 4 years would be ₹ ______
If for an immediate annuity r = 10% p.a., P = ₹ 12,679.46 and A = ₹ 18,564, then the amount of each annuity paid is ______
If payments of an annuity fall due at the beginning of every period, the series is called annuity ______
The intervening time between payment of two successive installments is called as ______
For annuity due,
C = ₹ 20,000, n = 3, I = 0.1, (1.1)–3 = 0.7513
Therefore, P = `square/0.1 xx [1 - (1 + 0.1)^square]`
= 2,00,000 [1 – 0.7513]
= ₹ `square`
