मराठी
महाराष्ट्र राज्य शिक्षण मंडळएचएससी वाणिज्य (इंग्रजी माध्यम) इयत्ता १२ वी

The present value of an immediate annuity for 4 years at 10% p.a. compounded annually is ₹ 23,400. It’s accumulated value after 4 years would be ₹ ______ - Mathematics and Statistics

Advertisements
Advertisements

प्रश्न

The present value of an immediate annuity for 4 years at 10% p.a. compounded annually is ₹ 23,400. It’s accumulated value after 4 years would be ₹ ______

रिकाम्या जागा भरा
Advertisements

उत्तर

34, 259.94

shaalaa.com
Annuity
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 2.2: Insurance and Annuity - Q.3

संबंधित प्रश्‍न

A person invested ₹ 5,000 every year in finance company that offered him interest compounded at 10% p.a., what is the amount accumulated after 4 years? [Given (1.1)4 = 1.4641]


Find accumulated value after 1 year of an annuity immediate in which ₹ 10,000 is invested every quarter at 16% p.a. compounded quarterly. [Given (1.04)4 = 1.1699]


Find the present value of an annuity immediate of ₹36,000 p.a. for 3 years at 9% p.a. compounded annually. [Given (1.09)−3 = 0.7722]


Find the present value of an ordinary annuity of ₹63,000 p.a. for 4 years at 14% p.a. compounded annually. [Given (1.14)−4 = 0.5921]


Find the rate of interest compounded annually if an annuity immediate at ₹20,000 per year amounts to ₹2,60,000 in 3 years.


In an ordinary annuity, payments or receipts occur at ______. 


Choose the correct alternative :

Rental payment for an apartment is an example of


______ is a series of constant cash flows over a limited period of time.


Fill in the blank :

The person who receives annuity is called __________.


Fill in the blank :

The intervening time between payment of two successive installments is called as ___________.


State whether the following is True or False :

The future value of an annuity is the accumulated values of all installments.


State whether the following is True or False :

Sinking fund is set aside at the beginning of a business.


Solve the following :

Find the amount of an ordinary annuity if a payment of ₹500 is made at the end of every quarter for 5 years at the rate of 12% per annum compounded quarterly. [(1.03)20 = 1.8061]


Solve the following :

Find the amount a company should set aside at the end of every year if it wants to buy a machine expected to cost ₹1,00,000 at the end of 4 years and interest rate is 5% p. a. compounded annually. [(1.05)4 = 1.21550625]


Solve the following :

Find the rate of interest compounded annually if an ordinary annuity of ₹20,000 per year amounts to ₹41,000 in 2 years.


Solve the following :

Find the future value after 2 years if an amount of ₹12,000 is invested at the end of every half year at 12% p. a. compounded half yearly. [(1.06)4 = 1.2625]


Solve the following :

After how many years would an annuity due of ₹3,000 p.a. accumulated ₹19,324.80 at 20% p. a. compounded yearly? [Given (1.2)4 = 2.0736]


Multiple choice questions:

Rental payment for an apartment is an example of ______


Multiple choice questions:

The present value of an immediate annuity of ₹ 10,000 paid each quarter for four quarters at 16% p.a. compounded quarterly is ______


State whether the following statement is True or False:

The relation between accumulated value ‘A’ and present value ‘P’ is A = P(1+ i)n 


State whether the following statement is True or False:

Annuity contingent begins and ends on certain fixed dates


State whether the following statement is True or False:

An annuity where payments continue forever is called perpetuity


If for an immediate annuity r = 10% p.a., P = ₹ 12,679.46 and A = ₹ 18,564, then the amount of each annuity paid is ______


The intervening time between payment of two successive installments is called as ______


A company decides to set aside a certain sum at the end of each year to create a sinking fund, which should amount to ₹ 4 lakhs in 4 years at 10% p.a. Find the amount to be set aside each year?
[Given (1.1)4 = 1.4641]


For annuity due,

C = ₹ 20,000, n = 3, I = 0.1, (1.1)–3 = 0.7513

Therefore, P = `square/0.1 xx [1 - (1 + 0.1)^square]`

= 2,00,000 [1 – 0.7513]

= ₹ `square`


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×