मराठी

A Beam of Light Consisting of Two Wavelengths, 800 Nm and 600 Nm is Used to Obtain the Interference Fringes in a Young'S Double Slit Experiment on a Screen Placed 1 ·

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प्रश्न

A beam of light consisting of two wavelengths, 800 nm and 600 nm is used to obtain the interference fringes in a Young's double slit experiment on a screen placed 1 · 4 m away. If the two slits are separated by 0·28 mm, calculate the least distance from the central bright maximum where the bright fringes of the two wavelengths coincide.

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उत्तर

Given: −

λ1 = 800 nm = 800 × 10−9 m

λ2 = 600 nm = 600 × 10−9 m

D = 1.4 m

= 0.28 mm = 0.28 × 10−3 m

Let n1th maximum corresponds to λ1 coincides with n2th maximum corresponds to λ2. Then,

`n_1(lambda_1D)/d =n_2 ((lambda_2)D)/d`

`or,n_1/n^2 =lambda^2/lambda^1 = 600/800 =3/4`

The minimum integral value of n1 is 3 and of n2 is 4. Therefore, the minimum value of is,

`y_(min) = n_1(lambda_1D)/d=(3 xx 800 xx 10^-9 xx 1.4)/((0.28) xx 10^-3)`

`y_(min) =12mm`

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2011-2012 (March) All India Set 1

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