मराठी
कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान इयत्ता ११

A 60 Kg Man Pushes a 40 Kg Man by a Force of 60 N. the 40 Kg Man Has Pushed the Other Man with a Force of

Advertisements
Advertisements

प्रश्न

A 60 kg man pushes a 40 kg man by a force of 60 N. The 40 kg man has pushed the other man with a force of

पर्याय

  • 40 N

  • 0 N

  • 60 N

  • 20 N

MCQ
Advertisements

उत्तर

60 N

According to Newton's third law, which states that an action-reaction pair of forces are equal in magnitude, the man who weighs 40 kg will push the other man with the same force of 60 N.

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 4: The Forces - MCQ [पृष्ठ ६२]

APPEARS IN

एचसी वर्मा Concepts of Physics Volume 1 and 2 [English]
पाठ 4 The Forces
MCQ | Q 4 | पृष्ठ ६२

संबंधित प्रश्‍न

State if the following statement is true or false. Give a reason for your answer.

Work done in the motion of a body over a closed loop is zero for every force in nature.


List all the forces acting on the block B in figure.


Figure shows a cart. Complete the table shown below.

Force on Force by Nature of the Force Direction
Cart

1
2
3
:

   
Horse

1
2
3
:

   
Driver

1
2
3
:

   

Which of the following systems may be adequately described by classical physics ?

(a) motion of a cricket ball
(b) motion of a dust particle
(c) a hydrogen atom
(d) a neutron changing to a proton.


Calculate the force with which you attract the earth.


A monkey is sitting on a tree limb. The limb exerts a normal force of 48 N and a frictional force of 20 N. Find the magnitude of the total force exerted by the limb on the monkey.


The average separation between the proton and the electron in a hydrogen atom in ground state is 5.3 × 10−11 m. (a) Calculate the Coulomb force between them at this separation. (b) When the atom goes into its first excited state the average separation between the proton and the electron increases to four times its value in the ground state. What is the Coulomb force in this state?


In tug of war, the team that exerts a larger tangential force on the ground wins. Consider the period in which a team is dragging the opposite team by applying a larger tangential force on the ground. List which of the following works are positive, which are negative and which are zero?

(a) work by the winning team on the losing team
(b) work by the losing team on the winning team
(c) work by the ground on the winning team
(d) work by the ground on the losing team
(e) total external work on the two teams.


The magnetic force on a charged particle is always perpendicular to its velocity. Can the magnetic force change the velocity of the particles? Speed of the particle?

 

A block of mass m slides down a smooth vertical circular track. During the motion, the block is in  


A block of mass 2 kg kept at rest on an inclined plane of inclination 37° is pulled up the plane by applying a constant force of 20 N parallel to the incline. The force acts for one second.  Show that the work done by the applied force does not exceed 40 J.


A force F = 20 + 10y acts on a particle in y-direction where F is in newton and y in metre. Work done by this force to move the particle from y – 0 to y – 1 m is:


The work done by an applied variable force, F = x + x3 from x = 0 m to x = 2m, where x is displacement, is:


A bicyclist comes to a skidding stop in 10 m. During this process, the force on the bicycle due to the road is 200 N and is directly opposed to the motion. The work done by the cycle on the road is ______.


A body of mass 0.5 kg travels in a straight line with velocity v = a x3/2 where a = 5 m–1/2s–1. The work done by the net force during its displacement from x = 0 to x = 2 m is ______.


A block of mass m is taken from A to B slowly under the action of a constant force R Work done by this force is ______.


A body is displaced from (0, 0) to (1 m, 1 m) along the path x = y by a force F = (x2`hat"J"` + y`hat"i"`)N. The work done by this force will be:


In the integration method for variable force, why do we divide displacement into tiny segments (ds)?


What does 'dW' represent in the variable force work calculation?


A particle moves under the effect of a force F = Cx from x = 0 to x = x1. The work done in the process is ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×