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The Magnetic Force on a Charged Particle is Always Perpendicular to Its Velocity. Can the Magnetic Force Change the Velocity of the Particles? Speed of the Particle?

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प्रश्न

The magnetic force on a charged particle is always perpendicular to its velocity. Can the magnetic force change the velocity of the particles? Speed of the particle?

 
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उत्तर

The magnetic force on a charged particle is always perpendicular to its velocity. Therefore, the work done by the magnetic force on the charged particle is zero. Here, the kinetic energy and speed of the particle remain unaffected, while the velocity changes due to the change in direction of its motion.

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पाठ 8: Work and Energy - Short Answers [पृष्ठ १३१]

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एचसी वर्मा Concepts of Physics Volume 1 and 2 [English]
पाठ 8 Work and Energy
Short Answers | Q 15 | पृष्ठ १३१

संबंधित प्रश्‍न

State if the following statement is true or false. Give a reason for your answer.

Work done in the motion of a body over a closed loop is zero for every force in nature.


Figure shows a cart. Complete the table shown below.

Force on Force by Nature of the Force Direction
Cart

1
2
3
:

   
Horse

1
2
3
:

   
Driver

1
2
3
:

   

Let E, G and N represent the magnitudes of electromagnetic gravitational and nuclear forces between two electrons at a given separation. Then


The sum of all electromagnetic forces between different particles of a system of charged particles is zero 


A neutron exerts a force on a proton which is

(a) gravitational
(b) electromagnetic
(c) nuclear
(d) weak


If all matters were made of electrically neutral particles such as neutrons,
(a) there would be no force of friction
(b) there would be no tension in the string
(c) it would not be possible to sit on a chair
(d) the earth could not move around the sun.


Calculate the force with which you attract the earth.


At what distance should two charges, each equal to 1 C, be placed so that the force between them equals your weight ?


A monkey is sitting on a tree limb. The limb exerts a normal force of 48 N and a frictional force of 20 N. Find the magnitude of the total force exerted by the limb on the monkey.


The force with which the earth attracts an object is called the weight of the object. Calculate the weight of the moon from the following data : The universal constant of gravitation G = 6.67 × 11−11 N−m2/kg2, mass of the moon = 7.36 × 1022 kg, mass of the earth = 6 × 1024 kg and the distance between the earth and the moon = 3.8 × 105 km. 


A block of mass m slides down a smooth vertical circular track. During the motion, the block is in  


A box is pushed through 4.0 m across a floor offering 100 N resistance. How much work is done by the resisting force?

 

A constant force of 2⋅5 N accelerates a stationary particle of mass 15 g through a displacement of 2⋅5 m. Find the work done and the average power delivered.

 

A block of weight 100 N is slowly moved up a smooth incline of inclination 37° by a person. Calculate the work done by the person in moving the block through a distance of 2 m, if the driving force is (a) parallel to the incline and (b) in the horizontal direction.

 

Find the average frictional force needed to stop a car weighing 500 kg at a distance of 25 m if the initial speed is 72 km/h.


A block of mass 2 kg kept at rest on an inclined plane of inclination 37° is pulled up the plane by applying a constant force of 20 N parallel to the incline. The force acts for one second.  Find the kinetic energy of the block at the instant the force ceases to act. Take g = 10 m/s2.


A bicyclist comes to a skidding stop in 10 m. During this process, the force on the bicycle due to the road is 200 N and is directly opposed to the motion. The work done by the cycle on the road is ______.


A body is moving unidirectionally under the influence of a source of constant power supplying energy. Which of the diagrams shown in figure correctly shows the displacement-time curve for its motion?


A cylinder of area 300 cm2 and length 10 cm made of material of specific gravity 0.8 is floated in water with its axis vertical. It is then pushed downward, so as to be just immersed. The work done by the agent who pushes the cylinder into the water is ______ J.


The work done by a variable force is calculated using the formula:


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