English
Karnataka Board PUCPUC Science Class 11

The Magnetic Force on a Charged Particle is Always Perpendicular to Its Velocity. Can the Magnetic Force Change the Velocity of the Particles? Speed of the Particle?

Advertisements
Advertisements

Question

The magnetic force on a charged particle is always perpendicular to its velocity. Can the magnetic force change the velocity of the particles? Speed of the particle?

 
Short/Brief Note
Advertisements

Solution

The magnetic force on a charged particle is always perpendicular to its velocity. Therefore, the work done by the magnetic force on the charged particle is zero. Here, the kinetic energy and speed of the particle remain unaffected, while the velocity changes due to the change in direction of its motion.

shaalaa.com
  Is there an error in this question or solution?
Chapter 8: Work and Energy - Short Answers [Page 131]

APPEARS IN

HC Verma Concepts of Physics Volume 1 and 2 [English]
Chapter 8 Work and Energy
Short Answers | Q 15 | Page 131

RELATED QUESTIONS

Is it true that the reaction of a gravitational force is always gravitational, of an electromagnetic force is always electromagnetic and so on?


List all the forces acting on (a) the pulley A, (b) the boy and (c) the block C in figure.


Figure shows a cart. Complete the table shown below.

Force on Force by Nature of the Force Direction
Cart

1
2
3
:

   
Horse

1
2
3
:

   
Driver

1
2
3
:

   

When Neils Bohr shook hand with Werner Heisenberg, what kind of force they exerted ?


Let E, G and N represent the magnitudes of electromagnetic gravitational and nuclear forces between two electrons at a given separation. Then


A satellite is projected vertically upwards from an earth station. At what height above the earth's surface will the force on the satellite due to the earth be reduced to half its value at the earth station? (Radius of the earth is 6400 km.)


The work done by all the forces (external and internal) on a system equals the change in ______.


A small block of mass m is kept on a rough inclined surface of inclination θ fixed in an elevator. the elevator goes up with a uniform velocity v and the block does not slide on the wedge. The work done by the force of friction on the block in time t will be 


A box is pushed through 4.0 m across a floor offering 100 N resistance. How much work is done by the resisting force?

 

A force \[F = \alpha + bx\]  acts on a particle in the x-direction, where a and b are constants. Find the work done by this force during a displacement from x = 0 to x = d. 

 
 

Find the average frictional force needed to stop a car weighing 500 kg at a distance of 25 m if the initial speed is 72 km/h.


A particle of mass m moves on a straight line with its velocity varying with the distance travelled, according to the equation  \[\nu = a\sqrt{x}\] , where a is a constant. Find the total work done by all the forces during a displacement from \[x = 0 \text{ to } x - d\] .

 

A block of mass 2.0 kg is pushed down an inclined plane of inclination 37° with a force of 20 N acting parallel to the incline. It is found that the block moves on the incline with an acceleration of 10 m/s2. If the block started from rest, find the work done (a) by the applied force in the first second, (b) by the weight of the block in the first second and (c) by the frictional force acting on the block in the first second. Take g = 10 m/s2.


A uniform chain of mass m and length l overhangs a table with its two third part on the table. Find the work to be done by a person to put the hanging part back on the table.

 

A block of mass 1 kg is placed at point A of a rough track shown in figure following. If slightly pushed towards right, it stops at point B of the track. Calculate the work done by the frictional force on the block during its transit from A to B.


A lawn roller is pulled along a horizontal surface through a distance of 20 m by a rope with a force of 200 N. If the rope makes an angle of 60° with the vertical while pulling, the amount of work done by the pulling force is:


A graph of potential energy V(x) verses x is shown in figure. A particle of energy E0 is executing motion in it. Draw graph of velocity and kinetic energy versus x for one complete cycle AFA.


A body is displaced from (0, 0) to (1 m, 1 m) along the path x = y by a force F = (x2`hat"J"` + y`hat"i"`)N. The work done by this force will be:


If a force varies linearly with displacement, the area under the F-s graph forms:


The work done by a variable force is calculated using the formula:


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×