मराठी

∫ 5 X 4 + 12 X 3 + 7 X 2 X 2 + X D X - Mathematics

Advertisements
Advertisements

प्रश्न

\[\int\frac{5 x^4 + 12 x^3 + 7 x^2}{x^2 + x} dx\]

बेरीज
Advertisements

उत्तर

\[\int\left( \frac{5 x^4 + 12 x^3 + 7 x^2}{x^2 + x} \right)dx\]

\[ = \int \frac{x^2 \left( 5 x^2 + 12x + 7 \right)}{x\left( x + 1 \right)}dx\]

 `= ∫ x {( 5 x^2 + 5x + 7x + 7 )}/{( x + 1 )}`

\[ = \int\frac{x\left( 5x\left( x + 1 \right) + 7\left( x + 1 \right) \right)}{\left( x + 1 \right)}dx\]

` = ∫ x{ ( 5x + 7 )( x + 1 )}/{( x + 1 )}dx`

\[ = \int\left( 5 x^2 + 7x \right)dx\]

\[ = \frac{5 x^3}{3} + \frac{7 x^2}{2} + C\]

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 19: Indefinite Integrals - Exercise 19.02 [पृष्ठ १५]

APPEARS IN

आरडी शर्मा Mathematics [English] Class 12
पाठ 19 Indefinite Integrals
Exercise 19.02 | Q 20 | पृष्ठ १५

व्हिडिओ ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्‍न

`int{sqrtx(ax^2+bx+c)}dx`

\[\int\frac{\sin^3 x - \cos^3 x}{\sin^2 x \cos^2 x} dx\]

\[\int \left( e^x + 1 \right)^2 e^x dx\]

\[\int\left( x + 2 \right) \sqrt{3x + 5}  \text{dx} \]

\[\int \cos^2 \text{nx dx}\]

\[\int\frac{\cos^3 x}{\sqrt{\sin x}} dx\]

\[\int\frac{1}{1 + \sqrt{x}} dx\]

\[\int\frac{\text{sin }\left( \text{2 + 3 log x }\right)}{x} dx\]

\[\  ∫    x   \text{ e}^{x^2} dx\]

\[\int \sec^4 2x \text{ dx }\]

\[\int \cos^5 x \text{ dx }\]

\[\int\frac{1}{4 x^2 + 12x + 5} dx\]

\[\int\frac{1}{\sqrt{\left( x - \alpha \right)\left( \beta - x \right)}} dx, \left( \beta > \alpha \right)\]

\[\int\frac{\left( 3\sin x - 2 \right)\cos x}{13 - \cos^2 x - 7\sin x}dx\]

\[\int\frac{1}{4 \cos x - 1} \text{ dx }\]

\[\int x^2 e^{- x} \text{ dx }\]

\[\int e^\sqrt{x} \text{ dx }\]

\[\int\frac{x^2 \tan^{- 1} x}{1 + x^2} \text{ dx }\]

\[\int \tan^{- 1} \sqrt{\frac{1 - x}{1 + x}} dx\]

\[\int\frac{x^2 \sin^{- 1} x}{\left( 1 - x^2 \right)^{3/2}} \text{ dx }\]

\[\int e^x \left( \cot x + \log \sin x \right) dx\]

\[\int\frac{e^x \left( x - 4 \right)}{\left( x - 2 \right)^3} \text{ dx }\]

\[\int\left( 2x + 3 \right) \sqrt{x^2 + 4x + 3} \text{  dx }\]

\[\int\frac{3 + 4x - x^2}{\left( x + 2 \right) \left( x - 1 \right)} dx\]

\[\int\frac{5x}{\left( x + 1 \right) \left( x^2 - 4 \right)} dx\]

\[\int\frac{2x - 3}{\left( x^2 - 1 \right) \left( 2x + 3 \right)} dx\]

\[\int\frac{x}{\left( x - 1 \right)^2 \left( x + 2 \right)} dx\]

\[\int\frac{x^2}{\left( x - 1 \right) \left( x + 1 \right)^2} dx\]

\[\int\frac{x}{\left( x + 1 \right) \left( x^2 + 1 \right)} dx\]

\[\int\frac{3}{\left( 1 - x \right) \left( 1 + x^2 \right)} dx\]

\[\int\sqrt{\cot \text{θ} d  } \text{ θ}\]

Write the anti-derivative of  \[\left( 3\sqrt{x} + \frac{1}{\sqrt{x}} \right) .\]


The value of \[\int\frac{\sin x + \cos x}{\sqrt{1 - \sin 2x}} dx\] is equal to


\[\int\frac{\sin x}{1 + \sin x} \text{ dx }\]

\[\int\frac{\left( \sin^{- 1} x \right)^3}{\sqrt{1 - x^2}} \text{ dx }\]

\[\int\frac{1}{1 - x - 4 x^2}\text{  dx }\]

\[\int\frac{1}{1 + 2 \cos x} \text{ dx }\]

\[\int \left( x + 1 \right)^2 e^x \text{ dx }\]

\[\int\frac{\log \left( 1 - x \right)}{x^2} \text{ dx}\]

Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×