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∫ 1 ( Sin − 1 X ) √ 1 − X 2 Dx - Mathematics

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प्रश्न

\[\int\frac{1}{\left( \sin^{- 1} x \right) \sqrt{1 - x^2}} \text{ dx} \]
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उत्तर

\[\text{ Let I} = \int\frac{1}{\sin^{- 1} x \cdot \sqrt{1 - x^2}}dx\]
\[\text{ Putting  sin}^{- 1} x = t\]
\[ \Rightarrow \frac{dx}{\sqrt{1 - x^2}} = dt\]
\[ \therefore I = \int\frac{dt}{t}\]
\[ = \text{ ln }\left| t \right| + C\]
` = \text{ ln }  | sin ^-1   x| + c                                                                                     ( ∵ t   =  sin ^-1  x ) `

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पाठ 19: Indefinite Integrals - Revision Excercise [पृष्ठ २०३]

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आरडी शर्मा Mathematics [English] Class 12
पाठ 19 Indefinite Integrals
Revision Excercise | Q 14 | पृष्ठ २०३

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