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SSC (English Medium) १० वीं कक्षा - Maharashtra State Board Important Questions for Geometry Mathematics 2

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Geometry Mathematics 2
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In triangle ABC, ∠C=90°. Let BC= a, CA= b, AB= c and let 'p' be the length of the perpendicular from 'C' on AB, prove that:

1. cp = ab

2. `1/p^2=1/a^2+1/b^2`

Appears in 1 question paper
Chapter: [2] Pythagoras Theorem
Concept: Right-angled Triangles and Pythagoras Property

In the given figure, ∠QPR = 90°, seg PM ⊥ seg QR and Q–M–R, PM = 10, QM = 8, find QR.

Appears in 1 question paper
Chapter: [2] Pythagoras Theorem
Concept: Theorem of Geometric Mean

For finding AB and BC with the help of information given in the figure, complete following activity.

AB = BC ..........

∴ ∠BAC =

∴ AB = BC = × AC

                 = × `sqrt8`

                 = × `2sqrt2`

                 =

Appears in 1 question paper
Chapter: [2] Pythagoras Theorem
Concept: Right-angled Triangles and Pythagoras Property

In the given figure, ∠DFE = 90°, FG ⊥ ED, If GD = 8, FG = 12, find (1) EG (2) FD and (3) EF

Appears in 1 question paper
Chapter: [2] Pythagoras Theorem
Concept: Right-angled Triangles and Pythagoras Property

Find the length diagonal of a rectangle whose length is 35 cm and breadth is 12 cm.

Appears in 1 question paper
Chapter: [2] Pythagoras Theorem
Concept: Right-angled Triangles and Pythagoras Property

In the given figure, M is the midpoint of QR. ∠PRQ = 90°. Prove that, PQ= 4PM– 3PR2.

Appears in 1 question paper
Chapter: [2] Pythagoras Theorem
Concept: Right-angled Triangles and Pythagoras Property

Walls of two buildings on either side of a street are parallel to each other. A ladder 5.8 m long is placed on the street such that its top just reaches the window of a building at the height of 4 m. On turning the ladder over to the other side of the street, its top touches the window of the other building at a height 4.2 m. Find the width of the street.

Appears in 1 question paper
Chapter: [2] Pythagoras Theorem
Concept: Right-angled Triangles and Pythagoras Property

In ∆ABC, AB = 10, AC = 7, BC = 9, then find the length of the median drawn from point C to side AB.

Appears in 1 question paper
Chapter: [2] Pythagoras Theorem
Concept: Right-angled Triangles and Pythagoras Property

In ∆ABC, point M is the midpoint of side BC. If, AB+ AC= 290 cm2, AM = 8 cm, find BC.

Appears in 1 question paper
Chapter: [2] Pythagoras Theorem
Concept: Apollonius Theorem

In the given figure, point T is in the interior of rectangle PQRS, Prove that, TS+ TQ= TP+ TR(As shown in the figure, draw seg AB || side SR and A-T-B)

Appears in 1 question paper
Chapter: [2] Pythagoras Theorem
Concept: Right-angled Triangles and Pythagoras Property

Four alternative answers for the following question are given. Choose the correct alternative and write its alphabet:

Out of the dates given below which date constitutes a Pythagorean triplet?

Appears in 1 question paper
Chapter: [2] Pythagoras Theorem
Concept: Pythagorean Triplet

Some question and their alternative answer are given. Select the correct alternative.

Altitude on the hypotenuse of a right angled triangle divides it in two parts of lengths 4 cm and 9 cm. Find the length of the altitude.

Appears in 1 question paper
Chapter: [2] Pythagoras Theorem
Concept: Apollonius Theorem

Some question and their alternative answer are given. Select the correct alternative.

 In ∆ABC, AB = \[6\sqrt{3}\] cm, AC = 12 cm, BC = 6 cm. Find measure of ∠A.

Appears in 1 question paper
Chapter: [2] Pythagoras Theorem
Concept: Apollonius Theorem

Find the height of an equilateral triangle having side 2a.

Appears in 1 question paper
Chapter: [2] Pythagoras Theorem
Concept: Apollonius Theorem

Find the length a diagonal of a rectangle having sides 11 cm and 60 cm.

Appears in 1 question paper
Chapter: [2] Pythagoras Theorem
Concept: Apollonius Theorem

Find the length of the hypotenuse of a right angled triangle if remaining sides are 9 cm and 12 cm.

Appears in 1 question paper
Chapter: [2] Pythagoras Theorem
Concept: Right-angled Triangles and Pythagoras Property

In ∆ABC, seg AP is a median. If BC = 18, AB2 + AC2 = 260, Find AP.

Appears in 1 question paper
Chapter: [2] Pythagoras Theorem
Concept: Apollonius Theorem

∆ABC is an equilateral triangle. Point P is on base BC such that PC = `1/3`BC, if AB = 6 cm find AP.

Appears in 1 question paper
Chapter: [2] Pythagoras Theorem
Concept: Similarity in Right Angled Triangles

In a trapezium ABCD, seg AB || seg DC seg BD ⊥ seg AD, seg AC ⊥ seg BC, If AD = 15, BC = 15 and AB = 25. Find A(▢ABCD)

Appears in 1 question paper
Chapter: [2] Pythagoras Theorem
Concept: Right-angled Triangles and Pythagoras Property

Find the length of the hypotenuse in a right angled triangle where the sum
of the squares of the sides making right angle is 169.
(A)15 (B) 13 (C) 5 (D) 12

Appears in 1 question paper
Chapter: [2] Pythagoras Theorem
Concept: Similarity in Right Angled Triangles
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