Definitions [43]
Define the term solution.
Homogeneous mixtures of two or more than two components are known as solutions.
Define Mole fraction.
The mole fraction of a particular component in a solution is the ratio of the number of moles of that component to the total number of moles of all the components present in the solution.
Define Molarity (M).
Molarity (M) is defined as the number of moles of the solute dissolved in one Litre (or one cubic decimetre) of solution.
It is expressed as:
Molarity (M) = `"Moles of solute"/"Volume of Solution in Litre"`
For example, a 0.25 mol L−1 (or 0.25 M) solution of NaOH means that 0.25 mol of NaOH has been dissolved in one litre (or one cubic decimetre).
It is defined as the number of moles of solute present in 1000 mL of the solution. Molarity is represented by M.
Molarity (M) = `"Number of moles of solute"/"Volume of solution in mL" xx 1000`
or
M = `"Weight of solute"/"Molar mass of solute × Volume of solution in mL" xx 1000`
Define molality.
Molality (m) is defined as the number of moles of the solute dissolved in one kilogram (Kg) of the solvent. The units of molality are moles per kilogram, i.e., mole kg−1. The molality is preferred over molarity if the volume of the solution is either expanding or contracting with temperature.
molality (m) = `"Number of mole of solute"/"mass of solvent (in kg)"`
Define Mass percentage.
The mass percentage of a component of a solution is defined as the mass of the solute in grammes present in 100 g of the solution. It is expressed as:
Mass % of a component = `"Mass of the component in the solution"/"Total mass of solution"xx100`
For example, if a solution is described as 10% glucose in water by mass, it means that 10 g of glucose is dissolved in 90 g of water, resulting in a 100 g solution. Concentration, described by mass percentage, is commonly used in industrial chemical applications. For example, a commercial bleaching solution contains a 3.62 mass percentage of sodium hypochlorite in water.
Define Molality.
Molality (m) is defined as the number of moles of the solute per kilogram (kg) of the solvent. It is expressed as:
Molality (m) = `"Moles of solute"/"Mass of solvent in Kg"`
Therefore, the unit of molality is mole per kg (mol kg−1).
If nB moles of solute are dissolved in W grams of solvent, then
Molality = `"n"_"B"/"W" xx 1000`
Define Normality.
Normality (N) of a solution is defined as the number of gram equivalents of the solute present in one liter of the solution. Normality is used in acid-based redox titrations.
Normality (N) = `"Number of gram equivalents of solute"/"Volume of solution in litre"`
Define azeotropes.
Azeotropes are the binary mixtures of solutions that have the same composition in liquid and vapour phases and that have constant boiling points.
Define Raoult’s law for the elevation of the boiling point of a solution.
The elevation in boiling point of a solution is directly proportional to the molal concentration (molality) of the solute in the solution.
ΔTb = Kb m
Where
ΔTb = Elevation in boiling point
Kb = Molal elevation constant (ebullioscopic constant)
m = Molality of the solution
Define the following terms :
a. Cryoscopic constant
b. Resistivity
Cryoscopic constant:
Molal depression constant or cryoscopic constant is the depression in the freezing point of a solution containing one mole of the non - volatile solute in one kilogram of solvent.
Resistivity or specific resistance:
Resistivity is defined as the resistance of the conductor that is 1 m long and 1 m2 in cross-sectional area.
Define the following term:
Molal elevation constant (Kb)
Molal elevation constant (Kb) is defined as the elevation in boiling point of a solution when one mole of a non-volatile solute is dissolved in one kilogram of a volatile solvent.
Define Freezing point.
The temperature at which the liquid and solid forms of a substance can exist together in equilibrium is called the freezing point of that substance.
Define Cryoscopic constant.
Cryoscopic constant or the Molal depression constant is defined as the depression in freezing point when one mole of non-volatile solute is dissolved in one kilogram of solvent. Its unit is K Kg mol−1.
Define Semipermeable membrane
Semipermeable membrane: It is a membrane which allows the solvent molecules, but not the solute molecules, to pass through it.
Semipermeable membrane is a film such as cellophane which has pores large enough to allow the solvent molecules to pass through them.
Define Osmosis.
The net spontaneous flow of solvent molecules into the solution or from more dilute solution to more concentrated solution through a semipermeable membrane is called osmosis.
Define the following term:
Hypotonic solution
The solution having lower osmotic pressure as compared to some other solution is referred to as a hypotonic solution.
Define osmotic pressure.
Osmotic pressure may be defined as the external pressure which should be applied to the solution in order to stop the phenomenon of osmosis, i.e., to stop the flow of solvent into the solution when the two are separated by a semipermeable membrane.
Define the following term:
isotonic solution
Two or more solutions exerting the same osmotic pressure are called an isotonic solution.
Define reverse osmosis.
The process of moving a solvent from a solution to a pure solvent through a semipermeable membrane while applying excessive pressure on the solution side is known as reverse osmosis.
Define van’t Hoff factor.
The ratio of the observed (experimental) value of a colligative property to the normal (calculated) value of the same property is termed as van’t Hoff factor, i.
The increase in boiling point of a solvent on addition of a non-volatile solute is called elevation of boiling point.
\[\Delta T_b=iK_bm\]
A membrane which allows only solvent molecules to pass through it but not solute molecules is called a semipermeable membrane.
The flow of solvent molecules through a semipermeable membrane from lower concentration to higher concentration is called osmosis.
The excess pressure that must be applied to a solution to stop the flow of solvent through a semipermeable membrane is called osmotic pressure.
Define the following term:
Kohlrausch’s Law.
It states that at infinite dilution, the molar conductance of an electrolyte is the sum of molar conductances of its ions with molar conductance of each ion multiplied with the number of ions present in the formula of the electrolyte.
A solution in which more solute can be dissolved at the same temperature is called an unsaturated solution.
The maximum amount of a solute that can be dissolved in a given amount of solvent at a specified temperature is called solubility.
The pressure exerted by vapours of a liquid over the liquid surface in equilibrium at a given temperature is called vapour pressure.
A solution is a homogeneous mixture of two or more components whose composition and properties are uniform throughout.
The component present in larger quantity in a solution is called the solvent.
The component present in smaller quantity in a solution is called the solute.
A solution which contains the maximum amount of solute dissolved at a given temperature and pressure is called a saturated solution.
Two solutions having the same osmotic pressure at a given temperature are called isotonic solutions.
A solution having higher osmotic pressure than another solution is called hypertonic solution.
A solution having lower osmotic pressure than another solution is called hypotonic solution.
The flow of solvent from solution to pure solvent through a semipermeable membrane when pressure greater than osmotic pressure is applied is called reverse osmosis.
The experimentally determined molar mass of a solute which is different from its expected (normal) molar mass is called abnormal molar mass.
The composition of a solution expressed quantitatively is called its concentration.
A solution which obeys Raoult’s law over the entire range of concentration is called an ideal solution.
For an ideal solution:
ΔHmix = 0
A solution which does not obey Raoult’s law over the entire range of concentration is called a non-ideal solution.
A binary liquid mixture which boils at a constant temperature with fixed composition is called an azeotrope.
- Large positive deviation → Minimum boiling azeotrope
- Large negative deviation → Maximum boiling azeotrope
The properties of solutions which depend only on the number of solute particles present and not on their nature are called colligative properties.
The decrease in vapour pressure of a solvent on adding a non-volatile solute is called lowering of vapour pressure.
\[\Delta p=p_1^0-p_1\]
Relative lowering:
\[\frac{p_1^0-p_1}{p_1^0}=x_2\]
For dilute solution:
\[\frac{p_1^0-p_1}{p_1^0}=\frac{n_2}{n_1}\]
\[=\frac{w_2M_1}{w_1M_2}\]
Formulae [6]
\[\mathrm{Volume}\%=\frac{\text{Volume of component}}{\text{Total volume of solution}}\times100\]
\[x_i=\frac{n_i}{n_1+n_2+\cdots+n_i}\]
For binary solution:
\[x_A=\frac{n_A}{n_A+n_B}\]
xA + xB = 1
\[m=\frac{\text{Moles of solute}}{\text{Mass of solvent in kg}}\]
\[M=\frac{\text{Moles of solute}}{\text{Volume of solution in litre}}\]
\[\mathrm{Mass}\%=\frac{\text{Mass of component in solution}}{\text{Total mass of solution}}\times100\]
\[\mathrm{ppm}=\frac{\text{Number of parts of component}}{\text{Total number of parts of all components}}\times10^6\]
Theorems and Laws [4]
State Henry’s law.
Henry’s law: The mass of a gas dissolved in a given volume of the liquid at constant temperature is directly proportional to the pressure of the gas present in equilibrium with the liquid.
Henry’s law relates solubility of a gas with external pressure. The law states that, “the
solubility of a gas in liquid at constant temperature is proportional to the pressure of
the gas above the solution”.
If S is the solubility of the gas in mol dm−3, then according to Henry’s law,
S ∝ P i.e. S = KP
where, P is the pressure of the gas in atmosphere, K is constant of proportionality and
has the unit of mol dm−3 atm−1.
State Henry’s law.
Henry’s law states that the partial pressure of a gas in the vapour phase is proportional to the mole fraction of the gas in the solution.
- Henry was the first to give a quantitative relationship between the pressure and solubility of a gas in a solvent, which is known as Henry’s law. The law states that at a constant temperature, the solubility of a gas in a liquid is directly proportional to the partial pressure of the gas present above the surface of the liquid or solution.
- Dalton, a contemporary of Henry, also concluded independently that the solubility of a gas in a liquid solution is a function of the partial pressure of the gas. If we use the mole fraction of a gas in the solution as a measure of its solubility, then it can be said that the mole fraction of gas in the solution is proportional to the partial pressure of the gas over the solution.
- The most commonly used form of Henry’s law states that “the partial pressure of the gas in the vapour phase (p) is proportional to the mole fraction of the gas (x) in the solution” and is expressed as:
p ∝ x
p = KH . x - Here, KH is Henry’s law constant. When a mixture of more than one gas is brought into contact with a solvent, each gaseous component dissolves in proportion to its partial pressure. That is why Henry’s law is applied to every gas, independent of the presence of other gases.
Statement:
At constant temperature, the solubility of a gas in a liquid is directly proportional to the partial pressure of the gas present above the surface of the liquid.
Mathematical Form:
p = KH x
Where
p = partial pressure of gas
x = mole fraction of gas
KH = Henry’s law constant
Raoult’s Law (For Volatile Liquids):
Statement:
For a solution of volatile liquids, the partial vapour pressure of each component is directly proportional to its mole fraction in the solution.
Mathematical Form:
\[p_1=p_1^0x_1\]
\[p_2=p_2^0x_2\]
Total Vapour Pressure (Dalton’s Law):
\[P_{total}=p_1+p_2\]
\[P_{total}=p_1^0x_1+p_2^0x_2\]
Raoult’s Law (For Non-Volatile Solute):
\[p=p^0x_{solvent}\]
Key Points
The factor used to account for the extent of association or dissociation of solute particles in solution is called van’t Hoff factor.
\[i=\frac{\text{Normal molar mass}}{\text{Abnormal molar mass}}\]
\[i=\frac{\text{Observed colligative property}}{\text{Calculated colligative property}}\]
\[i=\frac{\text{Total moles of particles after dissociation/association}}{\text{Total moles of particles before dissociation/association}}\]
Value of i
• For dissociation → i > 1
• For association → i < 1
• For no association/dissociation → i = 1
Important Questions [84]
- Define Molarity (M).
- Define Molality
- Arrange the Following in Decreasing Order of Solubility in Water: ( C H 3 ) 3 N , ( C H 3 ) 2 N H , C H 3 N H 2
- Define the Following Terms : Molarity
- Write the Name of Gas Released When Cu is Added to the Conc. Hno3
- State Henry’s law.
- Write the Name of Gas Released When Cu is Added to Dilute Hno3
- Why do gases always tend to be less soluble in liquids as the temperature is raised?
- Write the two applications of Henrys law.
- Gas (A) is more soluble in water than Gas (B) at the same temperature. Which one of the two gases will have the higher value of KH (Henry’s constant) and why
- Henry’s law constant for CO2 in water is 1.67 × 108 Pa at 298 K. Calculate the quantity of CO2 in 500 mL of soda water when packed under 2.5 atm CO2 pressure at 298 K.
- Solubility of gas in liquid decreases with increase in ______.
- Give Reasons for the Following : Aquatic Animals Are More Comfortable in the Cold Water than in Warm Water.
- Value of Henry's constant KH ______.
- State Henry’s law.
- State Henry'S Law. What is the Effect of Temperature on the Solubility of a Gas in a Liquid?
- Define azeotropes.
- Why Does a Solution Containing Non-volatile Solute Have Higher Boiling Point than the Pure Solvent ?
- State Raoult’S Law for a Solution Containing Volatile Components. Write Two Characteristics of the Solution Which Obey Raoult’S Law at All Concentrations.
- What type of deviation is shown by a mixture of ethanol and acetone? Give reason.
- Some Liquids on Mixing Form 'Azeotropes'. What Are 'Azeotropes'?
- What type of azeotrope is formed by positive deviation from Raoult’s law?
- In non-ideal solution, what type of deviation shows the formation of maximum boiling azeotropes?
- An azeotropic mixture of two liquids will have a boiling point lower than either of the two liquids when it ______.
- What is Meant by Negative Deviation from Raoult'S Law? Give an Example. What is the Sign of ∆Mixh for Negative Deviation?
- The vapour pressure of pure liquid X and pure liquid Y at 25°C are 120 mm Hg and 160 mm Hg respectively. If equal moles of X and Y are mixed to form an ideal solution
- State Raoult’S Law for the Solution Containing Volatile Components
- What is Meant by Positive Deviations from Raoult'S Law? Give an Example. What is the Sign of ∆Mixh for Positive Deviation?
- State Raoult'S Law for the Solution Containing Volatile Components. What is the Similarity Between Raoult'S Law and Henry'S Law?
- 30 G of Urea (M = 60 G Mol−1) is Dissolved in 846 G of Water. Calculate the Vapour Pressure of Water for this Solution If Vapour Pressure of Pure Water at 298 K is 23·8 Mm Hg.
- 1 mole of liquid A and 2 moles of liquid B make a solution having a total vapour pressure of 40 torr. The vapour pressure of pure A and pure B are 45 torr and 30 torr, respectively.
- Define an Ideal Solution and Write One of Its Characteristics.
- Assertion (A): The enthalpy of mixing Δmix H is equal to zero for an ideal solution. Reason (R): For an ideal solution the interaction between solute and solvent molecules is stronger
- What Type of Intermolecular Attractive Interaction Exists in the Pair of Methanol and Acetone?
- A Solution 0.1 M of Na2so4 is Dissolved to the Extent of 95%. What Would Be Its Osmotic Pressure at 027 ? C (R = 0.0821 L K-1 Mol-1) .
- Out of 0.1 Molal Aqueous Solution of Glucose and 0.1 Molal Aqueous Solution of Kcl, Which One Will Have Higher Boiling Point and Why?
- A solution of glucose (molar mass = 180 g mol–1) in water is labelled as 10% (by mass). What would be the molality and molarity of the solution ?
- Write One Difference in the Following: Coagulation and Peptization
- A non-volatile solute 'X' (molar mass = 50 g mol−1), when dissolved in 78 g of benzene reduced its vapour pressure to 90%. Calculate the Mass of X dissolved in the solution.
- Define the following term: Molal elevation constant (Kb)
- Calculate the boiling point elevation for a solution prepared by adding 10 g of MgCl2 to 200 g of water, assuming MgCl2 is completely dissociated.
- Arrange the Following in Increasing Order of Boiling Points: (Ch3)3 N, C2 H5 Oh, C2h5nh2
- Define the Term Colligative Properties
- Assertion (A): Elevation in boiling point is a colligative property. Reason (R): The lowering of vapour pressure of solution causes elevation in boiling point.
- 8 g of glucose, C6H12O6 (Molar Mass = 180 g mol−1) is dissolved in 1 kg of water in a sauce pan. At what temperature will this solution boil?
- Arrange the Following Increasing Order of Their Boiling Point: Ch3ch2oh,Ch3cho,Ch3 - O - Ch3
- Calculate the boiling point of solution when 4g of MgSO4 (M= 120 g mol-1) was dissolved in 100g of water, assuming MgSO4 undergoes complete ionization.
- Out of 1 M Glucose and 2 M Glucose, Which One Has a Higher Boiling Point and Why?
- Which of the following aqueous solution will have highest boiling point?
- Why is elevation of boiling point a colligative property?
- If the molality of a dilute solution is doubled, the value of the molal elevation constant (Kb) will be ______.
- Account for the Following : H2s Has Lower Boiling Point than H2o.
- Calculate the freezing point of the solution when 31 g of ethylene glycol (C2H6O2) is dissolved in 500 g of water.
- Calculate the amount of CaCl2 (molar mass = 111 g mol−1) which must be added to 500 g of water to lower its freezing point by 2 K, assuming CaCl2 is completely dissociated.
- Calculate the freezing point of solution when 1.9 g of MgCl2 (M = 95 g mol−1) was dissolved in 50 g of water, assuming MgCl2 undergoes complete ionization.
- When 2.56 g of sulphur was dissolved in 100 g of CS2, the freezing point lowered by 0.383 K. Calculate the formula of sulphur (Sx).
- Calculate the Freezing Point of a Solution Containing 60 G of Glucose (Molar Mass = 180 G Mol–1) in 250 G of Water. (Kf of Water = 1.86 K Kg Mol–1)
- Give Reasons for the Following: Measurement of Osmotic Pressure Method is Preferred for the Determination of Molar Masses of Macromolecules Such as Proteins and Polymers.
- A 4% Solution(W/W) of Sucrose (M = 342 G Mol–1) in Water Has a Freezing Point of 271.15 K. Calculate the Freezing Point of 5% Glucose (M = 180 G Mol–1) in Water.
- A 4% Solution(W/W) of Sucrose (M = 342 G Mol−1) in Water Has a Freezing Point of 271.15 K.
- When 25.6 g of sulphur was dissolved in 1000 g of benzene, the freezing point lowered by 0.512 K. Calculate the formula of sulphur (Sr).
- Out of the following 1.0 M aqueous solution, which one will show the largest freezing point depression?
- Determine the osmotic pressure of a solution prepared by dissolving 2.32 × 10−2 g of K2SO4 in 2L of solution at 25°C assuming that K2SO4 is completely dissociated.
- A solution containing 15 g urea (molar mass = 60 g mol–1) per litre of solution in water has the same osmotic pressure (isotonic) as a solution of glucose (molar mass = 180 g mol–1) in water.
- Blood Cells Are Isotonic with 0.9% Sodium Chloride Solution. What Happens If We Place Blood Cells in a Solution Containing
- Assertion (A) : Osmotic pressure is a colligative property. Reason (R) : Osmotic pressure is proportional to the molality.
- Calculate the Mass of Nacl (Molar Mass = 58.5 G Mol−1) to Be Dissolved in 37.2 G of Water to Lower the Freezing Point by 2°C, Assuming that Nacl Undergoes Complete Dissociation.
- Determine the osmotic pressure of a solution prepared by dissolving 2.5 × 10−2 g of K2SO4 in 2L of water at 25°C, assuming that it is completely dissociated.
- Calculate the Mass of a Compound (Molar Mass = 256 G Mol−1) to Be Dissolved in 75 G of Benzene to Lower Its Freezing Point by 0.48 K (Kf = 5.12 K Kg Mol−1).
- What Happens When the External Pressure Applied Becomes More than the Osmotic Pressure of Solution?
- Define reverse osmosis.
- Which of the Two Components of Starch is Water Soluble?
- An unripe mango placed in a concentrated salt solution to prepare pickle, shrivels because ______.
- Why are aquatic species more comfortable in cold water in comparison to warm water?
- Why is the value of van't Hoff factor for ethanoic acid in benzene close to 0.5?
- Why is boiling point of 1 M NaCl solution more than that of 1 M glucose solution?
- 3.9 g of benzoic acid dissolved in 49 g of benzene shows a depression in freezing point of 1.62 K. Calculate the van't Hoff factor and predict the nature of solute (associated or dissociated).
- Define van’t Hoff factor.
- Define the Term Abnormal Molar Mass
- How Will You Convert the Following in Not More than Two Steps: Benzoic Acid to Benzaldehyde
- How Will You Convert the Following in Not More than Two Steps: Acetophenone to Benzoic Acid
- Predict Whether Van’T Hoff Factor, (I) is Less than One Or Greater than One in the Following: Ch3cooh Dissolved in Water
- Give Reasons for the Following Elevation of the Boiling Point of 1 M Kcl Solution is Nearly Double than that of 1 M Sugar Solution.
- When 19.5 g of F – CH2 – COOH (Molar mass = 78 g mol−1), is dissolved in 500 g of water, the depression in freezing point is observed to be 1°C.
Concepts [22]
- Introduction of Solution
- Expressing Concentration of Solutions
- Introduction of Solubility
- Solubility of a Solid in a Liquid
- Solubility of a Gas in a Liquid
- Vapour Pressure of Liquid Solutions - Introduction
- Vapour Pressure of Liquid- Liquid Solutions
- Raoult’s Law as a Special Case of Henry’s Law
- Vapour Pressure of Solutions of Solids in Liquids
- Ideal and Non-ideal Solutions
- Colligative Properties and Determination of Molar Mass - Introduction
- Relative Lowering of Vapour Pressure
- Elevation of Boiling Point
- Depression of Freezing Point
- Osmosis and Osmotic Pressure
- Reverse Osmosis and Water Purification
- Abnormal Molar Masses
- Solution Numericals
- Quantitative Concentration Numericals
- Composition of Vapour Phase
- Overview of Solutions
- Kohlrausch's law
