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The vapour pressure of pure liquid X and pure liquid Y at 25°C are 120 mm Hg and 160 mm Hg respectively. If equal moles of X and Y are mixed to form an ideal solution - Chemistry

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Question

The vapour pressure of pure liquid X and pure liquid Y at 25°C are 120 mm Hg and 160 mm Hg respectively. If equal moles of X and Y are mixed to form an ideal solution, calculate the vapour pressure of the solution.

Numerical
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Solution

At 25°C, Pure vapour pressure of liquid X and Y are

P0X = 120 mm Hg and P0Y = 160 mm Hg

Let the number of moles of liquid X and Y be ‘n’

XX = `n/(n + n)`

then, XX = XY = `1/2` = 0.5

Total vapour pressure of solution will be,

PT = P0X XX + P0Y XY

= 120 × 0.5 + 160 × 0.5

= 60 + 80

= 140 mm of Hg

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