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When 25.6 g of sulphur was dissolved in 1000 g of benzene, the freezing point lowered by 0.512 K. Calculate the formula of sulphur (Sr).

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Question

When 25.6 g of sulphur was dissolved in 1000 g of benzene, the freezing point lowered by 0.512 K. Calculate the formula of sulphur (Sr).

(Kf for benzene = 5.12 K kg mol−1, Atomic mass of sulphur = 32 g mol−1)

Numerical
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Solution

Kf for benzene = 5.12 K kg mol−1

WB = mass of solute = 25.6 g

WA = 1000 g

ΔTf = 5.12 K kg mol−1

Atomic mass of sulphur = 32 g mol−1

MB = `("K"_"f" xx "W"_"B" xx 1000)/(Δ"T"_"f" xx "W"_"A")`

= `(5.12 xx 25.6 xx 1000)/(0.512 xx 1000)`

= `131.072/0.152`

= 256

Now the molecular mass of

Sx = x × 32 = 256

x = `256/32` = 8

Therefore, the formula of sulphur = S8.

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2022-2023 (March) Delhi Set 1

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