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Revision: Calculus >> Integrals Maths Commerce (English Medium) Class 12 CBSE

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Definitions [12]

Definition: Indefinite Integral

The collection of all anti-derivatives of a function is called its indefinite integral.

\[\int f(x) dx = F(x) + C\]

Here: f(x) = integrand, dx = variable of integration, C = constant of integration.

Definition: Definite Integral

A definite integral is connected with finding the area under a curve over a given interval. The chapter introduction presents area as one of the central motivating ideas behind integral calculus.

\[\int_{a}^{b} f(x) dx\]
Definition: Antiderivative

If the derivative of a function F(x) is f(x), then F(x) is called an antiderivative or integral of f(x). The set of all such antiderivatives is written as:

\[\int f(x) dx = F(x) + C\]

where C is an arbitrary constant called the constant of integration.

Definition: Integration by Substitution

Integration by substitution is a method in which we replace a part of the integral by a new variable to simplify the integration.

General Formula:

If \[x = g(t), \ dx = g'(t) dt\] then \[\int f(x) dx = \int f(g(t))g'(t) dt\]

Definition: Integration using Trigonometric Identities

Integration using trigonometric identities means converting a trigonometric expression into an easier form with the help of standard identities before integrating.

Definition: Integration Using Partial Fraction

Integration by partial fractions is a method used to integrate rational functions, that is, functions of the form

\[\frac{p(x)}{q(x)}\], where both numerator and denominator are polynomials.
Definition: Integration by Parts

If two functions are written in the form uu and dvdv, then integration by parts is based on the product rule of differentiation.

\[\int\left(\mathrm{u.v}\right)\mathrm{dx}=\mathrm{u}\int\mathrm{v}\mathrm{dx}-\int\left(\frac{\mathrm{du}}{\mathrm{dx}}\right).\left(\int\mathrm{v}\mathrm{dx}\right)\mathrm{dx}\]

Definition: Definite integral

A definite integral represents the value of a function accumulated between two limits.
It can also be interpreted geometrically as the net area between the graph of y = f(x) and the x-axis from x = a to x = b.

Definition: Area Function

If a function f is continuous on an interval, the area function is defined by

\[A(x) = \int_{a}^{x} f(t) \, dt\]

This means that A(x) gives the area accumulated from x = a to a variable point x.

Definition: Definite Integral

If f(x) is a continuous function defined on an interval [a, b] and if Φ(x) is the antiderivative of f(x), i.e., \[\frac{d}{dx}[\phi(x)]=f(x)\] then the definite integral of f(x) over [a, b] denoted by \[\int_{a}^{b}f(x)dx\]  is defined as

\[\int_{a}^{b}f(x)dx=
\begin{bmatrix}
\phi\left(x\right)
\end{bmatrix}_{a}^{b}=\phi\left(b\right)-\phi\left(a\right)\]

Definition: Integration

\[\mathrm{If~}\frac{d}{dx}[F(x)]=f(x),\mathrm{~then~}\int f(x)dx=F(x)\]

Integration is the inverse process of differentiation.

Definition: Constant of Integration

\[\int f(x)dx=F(x)+c\]

  • The arbitrary constant 'c' is called the constant of integration.
  • F(x) + c is called the indefinite integral.

Formulae [12]

Formula: Integral Formulas
No. Derivatives Integrals (Anti-derivatives)
(i) \[\frac{d}{dx} \left( \frac{x^{n+1}}{n+1} \right) = x^n\]; \[\int x^n dx = \frac{x^{n+1}}{n+1} + \text{C}, n \neq -1\]
  \[\frac{d}{dx} (x) = 1\]; \[\int dx = x + \text{C}\]
(ii) \[\frac{d}{dx} (\sin x) = \cos x\]; \[\int \cos x dx = \sin x + \text{C}\]
(iii) \[\frac{d}{dx} (-\cos x) = \sin x\]; \[\int \sin x dx = -\cos x + \text{C}\]
(iv) \[\frac{d}{dx} (\tan x) = \sec^2 x\]; \[\int \sec^2 x dx = \tan x + \text{C}\]
(v) \[\frac{d}{dx} (-\cot x) = \text{cosec}^2 x\]; \[\int \text{cosec}^2 x dx = -\cot x + \text{C}\]
(vi) \[\frac{d}{dx} (\sec x) = \sec x \tan x\]; \[\int \sec x \tan x dx = \sec x + \text{C}\]
(vii) \[\frac{d}{dx} (-\text{cosec} x) = \text{cosec} x \cot x\]; \[\int \text{cosec} x \cot x dx = -\text{cosec} x + \text{C}\]
(viii) \[\frac{d}{dx} (\sin^{-1} x) = \frac{1}{\sqrt{1-x^2}}\]; \[\int \frac{dx}{\sqrt{1-x^2}} = \sin^{-1} x + \text{C}\]
(ix) \[\frac{d}{dx} (-\cos^{-1} x) = \frac{1}{\sqrt{1-x^2}}\]; \[\int \frac{dx}{\sqrt{1-x^2}} = -\cos^{-1} x + \text{C}\]
(x) \[\frac{d}{dx} (\tan^{-1} x) = \frac{1}{1+x^2}\]; \[\int \frac{dx}{1+x^2} = \tan^{-1} x + \text{C}\]
(xi) \[\frac{d}{dx} (e^x) = e^x\]; \[\int e^x dx = e^x + \text{C}\]
(xii) \[\frac{d}{dx}\left(\log|x|\right)=\frac{1}{x};\] \[\int\frac{1}{x}dx=\log|x|+\mathrm{C}\]
(xiii) \[\frac{d}{dx} \left( \frac{a^x}{\log a} \right) = a^x\]; \[\int a^x dx = \frac{a^x}{\log a} + \text{C}\]
Fundamental Integration Formulae
  • \[\int \frac{dx}{x^2 - a^2} = \frac{1}{2a} \log \left| \frac{x - a}{x + a} \right| + C\]
  • \[\int \frac{dx}{a^2 - x^2} = \frac{1}{2a} \log \left| \frac{a + x}{a - x} \right| + C\]
  • \[\int \frac{dx}{x^2 + a^2} = \frac{1}{a} \tan^{-1} \left(\frac{x}{a}\right) + C\]
  • \[\int \frac{dx}{\sqrt{x^2 - a^2}} = \log \left| x + \sqrt{x^2 - a^2} \right| + C\]
  • \[\int \frac{dx}{\sqrt{a^2 - x^2}} = \sin^{-1} \left(\frac{x}{a}\right) + C\]
  • \[\int \frac{dx}{\sqrt{x^2 + a^2}} = \log \left| x + \sqrt{x^2 + a^2} \right| + C\]
Formula: Two Important Forms (Substitution)
  1. \[\int[f(x)]^nf^{\prime}(x)dx=\frac{[f(x)]^{n+1}}{n+1}+c\quad(n\neq-1)\]
  2. \[\int\frac{f^{\prime}(x)}{f(x)}dx=\log|f(x)|+c\]

Formula: Trigonometric Identities Used in Integration
Expression Equivalent Form
\[\sin^2x+\cos^2x\]  1
\[1+\tan^2x\] \[sec^2x\]
\[1+\cot^2x\] \[cosec^2x\]
\[\sin^2x\] \[\frac{1-\cos2x}{2}\]
\[\cos^2x\] \[\frac{1+\cos2x}{2}\]
sin x cos x \[\frac{1}{2}\sin2x\]
sin x cos y \[\frac{1}{2}[\sin(x+y)+\sin(x-y)]\]
cos x sin y \[\frac{1}{2}[\sin(x+y)-\sin(x-y)]\]
cos x cos y \[\frac{1}{2}[\cos(x+y)+\cos(x-y)]\]
sin x sin y \[\frac{1}{2}[\cos(x-y)-\cos(x+y)]\]
1 - cos x  \[2\sin^2\frac{x}{2}\]
1 + cos x  \[2\cos^2\frac{x}{2}\]
\[\sin^3x\] \[\frac{1}{4}(3\sin x-\sin3x)\]
\[cos^3x\] \[\frac{1}{4}(3\cos x+\cos3x)\]
Formula: Logarithmic Integrals
Function Integral
\[\int\tan x\mathrm{~}dx\] \[\log|\sec x|+c\]
\[\int\cot x\mathrm{~}dx\] \[\log|\sin x|+c\]
\[\int\sec x\operatorname{d}x\] \[\log|\sec x+\tan x|+c\]
\[\int cosecxdx\] \[\log|\left(\csc x-\cot x\right)|+c\]
Formula: Special Integral Form

\[\int e^x\left[\left.f(x)+f^{\prime}(x)\right.\right]dx=e^xf(x)+c\]

Formula: Integration by Substitution

If, u = f(x) ⇒ \[\frac{du}{dx}=f^{\prime}(x)\]

then \[\int[f(x)]^nf^{\prime}(x)dx=\frac{[f(x)]^{n+1}}{n+1}+c\quad(n\neq-1)\]

Linear Substitution Rule:

If u = ax + bu = , then

\[\int(ax+b)^ndx=\frac{(ax+b)^{n+1}}{a(n+1)}+c\quad(n\neq-1)\]

Formula: Standard Forms
No. Differentiation Integration
1 \[\frac{d}{dx}(x^{n+1})=(n+1)x^n\] \[\int x^ndx=\frac{x^{n+1}}{n+1}+c\]
2 \[\frac{d}{dx}(\log x)=\frac{1}{x}\] \[\int\frac{1}{x}dx=\log\mid x\mid+c\]
3 \[\frac{d}{dx}(e^x)=e^x\] \[\int e^{x}dx=e^{x}+c\]
4 \[\frac{d}{dx}(a^x)=a^x\log_ea\] \[\int a^{x}dx=\frac{a^{x}}{\log_{e}a}+c(a>0,a\neq1)\]
5 \[\frac{d}{dx}(\sin x)=\cos x\] \[\int\cos xdx=\sin x+c\]
6 \[\frac{d}{dx}(\cos x)=-\sin x\] \[\int\sin xdx=-\cos x+c\]
7 \[\frac{d}{dx}(\tan x)=\sec^2x\] \[\int\sec^2xdx=\tan x+c\]
8

\[\frac{d}{dx}(\cot x)=-\mathrm{cosec}^{2}x\]

\[\int\mathrm{cosec}^2xdx=-\cot x+c\]
9 \[\frac{d}{dx}(\sec x)=\sec x\tan x\] \[\int\sec x\tan xdx=\sec x+c\]
10 \[\frac{d}{dx}(\operatorname{cosec}x)=-\operatorname{cosec}x\cot x\] \[\int\operatorname{cosec}x\cot xdx=-\operatorname{cosec}x+c\]
11

\[\frac{d}{dx}(\sin^{-1}x)=\frac{1}{\sqrt{1-x^2}}\]

\[\frac{d}{dx}(\cos^{-1}x)=\frac{-1}{\sqrt{1-x^{2}}}\]

\[\begin{aligned}
 & \int{\frac{1}{\sqrt{1-x^{2}}}}dx=\sin^{-1}x+c \\
\mathrm{OR} & =-\cos^{-1}x+c
\end{aligned}\]
12

\[\frac{d}{dx}(\tan^{-1}x)=\frac{1}{1+x^2}\]

\[\frac{d}{dx}(\cot^{-1}x)=\frac{-1}{1+x^{2}}\]

\[\int\frac{1}{1+x^{2}}dx=\tan^{-1}x+c\mathrm{OR}=-\cot^{-1}x+c\]
13

\[\frac{d}{dx}(\sec^{-1}x)=\frac{1}{x\sqrt{x^{2}-1}}\]

\[\frac{d}{dx}(\mathrm{cosec}^{-1}x)=\frac{-1}{x\sqrt{x^{2}-1}}\]

\[\int\frac{1}{x\sqrt{x^{2}-1}}dx=\sec^{-1}x+cOR=-cosec^{-1}x+c\]
14 \[\frac{d}{dx}\left(\sin^{-1}\frac{x}{a}\right)=\frac{1}{\sqrt{a^{2}-x^{2}}}\] \[\int\frac{dx}{\sqrt{a^{2}-x^{2}}}=\sin^{-1}\frac{x}{a}+c\]
15 \[\frac{d}{dx}\left(\tan^{-1}\frac{x}{a}\right)=\frac{a}{a^2+x^2}\] \[\int\frac{dx}{a^{2}+x^{2}}=\frac{1}{a}\tan^{-1}\frac{x}{a}+c\]
16 \[\frac{d}{dx}\left(\sec^{-1}\frac{x}{a}\right)=\frac{a}{x\sqrt{x^{2}-a^{2}}}\] \[\int\frac{dx}{x\sqrt{x^{2}-a^{2}}}dx=\frac{1}{a}\sec^{-1}\frac{x}{a}+c\]
Formula: Integration by Parts

Statement:

If f(x) and g(x) are any two differentiable functions of x and G(x) is the antiderivative of g(x), i.e., \[G(x)=\int g(x)dx\]. Then 

\[\int f(x)g(x)dx=f(x)G(x)-\int f^{\prime}(x)G(x)dx\]

Formula: Essential Integrals
Integral Result
\[\int\frac{dx}{x^2+a^2}\] \[\frac{1}{a}\tan^{-1}\left(\frac{x}{a}\right)+c\]
\[\int\frac{dx}{x^2-a^2}\] \[\frac{1}{2a}\log\left|\frac{x-a}{x+a}\right|+c\]
\[\int\frac{dx}{a^2-x^2}\] \[\frac{1}{2a}\log\left|\frac{a+x}{a-x}\right|+c\]
Formula: Partial Fractions

(A) Non-repeated linear factors

\[\frac{Ax+B}{(x-a)(x-b)}=\frac{A}{x-a}+\frac{B}{x-b}\]

(B) Repeated linear factor

\[\frac{Ax+B}{(x-a)^n}=\frac{A_1}{x-a}+\frac{A_2}{(x-a)^2}+\cdots+\frac{A_n}{(x-a)^n}\]

(C) Quadratic factor (not factorisable)

\[\frac{Ax+B}{ax^2+bx+c}\]

Formula: Square Root Integrals

1.\[\int\sqrt{(a^{2}-x^{2})}dx=\frac{1}{2}x\sqrt{(a^{2}-x^{2})}+\frac{1}{2}a^{2}\sin^{-1}\left(\frac{x}{a}\right)+c\]

2. \[\int\left(\sqrt{a^{2}+x^{2}}\right)dx=\frac{1}{2}x\sqrt{(a^{2}+x^{2})}+\frac{1}{2}a^{2}\log|x+\sqrt{(a^{2}+x^{2})}|+c\]

Theorems and Laws [4]

Prove that: `int sqrt(a^2 - x^2) * dx = x/2 * sqrt(a^2 - x^2) + a^2/2 * sin^-1(x/a) + c`

Let I = `int sqrt(a^2 - x^2) dx`

= `int sqrt(a^2 - x^2)*1 dx`

= `sqrt(a^2 - x^2)* int 1 dx - int [d/dx (sqrt(a^2 - x^2))* int 1 dx]dx`

= `sqrt(a^2 - x^2)*x - int [1/(2sqrt(a^2 - x^2))*d/dx (a^2 - x^2)*x]dx`

= `sqrt(a^2 - x^2)*x - int 1/(2sqrt(a^2 - x^2))(0 - 2x)*x  dx`

= `sqrt(a^2 - x^2)*x - int (-x)/sqrt(a^2 - x^2)*x  dx`

= `xsqrt(a^2 - x^2) - int (a^2 - x^2 - a^2)/sqrt(a^2 - x^2)dx`

= `xsqrt(a^2 - x^2) - int sqrt(a^2 - x^2)dx + a^2 int dx/sqrt(a^2 - x^2)`

= `xsqrt(a^2 - x^2) - I + a^2sin^-1(x/a) + c_1`

∴ 2I = `xsqrt(a^2 - x^2) + a^2sin^-1(x/a) + c_1`

∴ I = `x/2 sqrt(a^2 - x^2) + a^2/2 sin^-1(x/a) + c_1/2`

∴ `int sqrt(a^2 - x^2)dx = x/2 sqrt(a^2 - x^2) + a^2/2sin^-1(x/a) + c`, where `c = c_1/2`.

Theorem: First Fundamental Theorem

If f is continuous on [a, b] and

\[A(x) = \int_{a}^{x} f(t) \, dt\] 
then A'(x) = f(x) for every x in (a, b).
This means the derivative of the accumulated area
function is the original function itself.
Theorem: Second Fundamental Theorem

If f is continuous on [a, b] and F is any antiderivative of f, then

\[\int_{a}^{b} f(x) \, dx = F(b) - F(a)\]

This is the formula most often used in exams to evaluate definite integrals.

Theorem: Fundamental Theorem of Calculus

Theorem 1:

 Let f be a continuous function on the closed interval [a, b] and let A (x) be the area function. Then A′(x) = f (x), for all x ∈ [a, b]

Theorem 2:

Let f  be a continuous function defined on the closed interval [a, b], and F be an antiderivative of f. Then  \[\int_a^bf(x)dx=\left[\mathbf{F}(x)\right]_a^b=\mathbf{F}(b)-\mathbf{F}(a)\]

Key Points

Key Points: Introduction of Integrals
  • Primitive
    Another name for anti-derivative.
  • Indefinite Integral
    The family of all anti-derivatives of a function.
  • Definite Integral
    An integral taken between two fixed limits, commonly used to represent area or total accumulation.
  • Integral Calculus
    The branch of calculus dealing with anti-derivatives, accumulation, and areas under curves.
Key Points: Integration as an Inverse Process of Differentiation
  • Integration is the inverse process of differentiation.

  • The result of indefinite integration is called the antiderivative or primitive.

  • General form: ∫f(x) dx = F(x) + C.

  • The constant CC must always be added in indefinite integrals.

Key Points: Properties of Indefinite Integral
Property Formula
Reverse of differentiation \[\frac{d}{dx}\left(\int f(x) dx\right) = f(x)\]
Same derivative \[F'(x) = G'(x) \Rightarrow F(x) = G(x) + C\]
Sum rule \[\int (f + g)dx = \int fdx + \int gdx\]
Difference rule \[\int (f - g)dx = \int fdx - \int gdx\]
Constant multiple rule \[\int k f(x)dx = k \int f(x)dx\]
General linearity \[\int (kf \pm lg)dx = k \int fdx \pm l \int gdx\]
Key Points: Standard Substitution
  • Integration by substitution is the reverse process of the chain rule.

  • Choose the substitution so that the integral becomes simpler, not more complicated.

  • Always rewrite both the function and \(dx\) in terms of the new variable.

  • For indefinite integrals, back-substitute and add \(C\).

  • For definite integrals, limits should also be changed if the solution is continued in the new variable.

  • Trigonometric substitution is mainly used for radicals involving \(a^2-x^2\), \(x^2+a^2\), and \(x^2-a^2\).

Key Points: Integration Using Trigonometric Identities
  • First inspect the pattern in the integrand.

  • Do not integrate complicated trigonometric expressions directly if an identity can simplify them first.

  • After simplification, integrate term by term carefully.

  • Always add the constant of integration, \(C\).

Key Points : Partial Fractions
  • First check whether the rational function is proper or improper.

  • Use long division before decomposition if the fraction is improper.

  • Factorise the denominator completely before choosing partial fractions.

  • For each distinct linear factor, use a constant numerator such as A, B, or C.

  • For a repeated linear factor, include every power separately.

  • For an irreducible quadratic factor, use a linear numerator of the form Bx + C.

  • After decomposition, integrate each term separately using standard formulas.

Key Points: Integration by Parts
  • Formula:

    \[\int u dv = uv - \int v du\]
  • Choose u by LIATE

  • For log x and inverse trig, multiply by 1

  • Repeated parts may be needed for \[e^x \sin x\], \[e^x \cos x\].

Key Points: Integrals of Some Particular Functions
  • Convert the integrand into a known standard form before integrating.

  • For \[x^2 - a^2\], factorize and use partial fractions.

  • For \[x^2 + a^2\], the answer usually involves \[\tan^{-1}\].

  • For \[\sqrt{a^2 - x^2}\], the answer usually involves \[\sin^{-1}\].

  • For general quadratics, complete the square first.

  • For \[px + q\] in the numerator, relate it to the derivative of the denominator.

  • Always write the constant of integration C in the final answer.

Key Points: Definite Integrals
  • Used to find exact accumulated value over a fixed interval.

  • Written as \[\int_{a}^{b} f(x) \, dx\].

  • Evaluated using \[F(b) - F(a)\].

  • Gives a unique numerical value.

  • Represents net area geometrically.

Key Points: Fundamental Theorem of Integral Calculus
  • The theorem connects differentiation and integration.

  • If \[A(x) = \int_{a}^{x} f(t) \, dt\], then \[A'(x) = f(x)\].

  • If  F'(x) = f(x), then \[\int_{a}^{b} f(x) \, dx = F(b) - F(a)\].

  • The result is used to evaluate definite integrals quickly.

  • The function should be continuous on the interval for direct use of the theorem.

Key Points: Evaluation of Definite Integrals by Substitution
  • Look for an inner function and its derivative.

  • Choose substitution carefully.

  • Change the limits immediately.

  • Integrate in the new variable.

  • Do not add +C in a definite integral.

Key Points: LIATE Rule

For choosing the first function:

L I A T E

  • Logarithmic

  • Inverse trigonometric

  • Algebraic

  • Trigonometric

  • Exponential

Key Points: Properties of Indefinite Integrals

1.\[\frac{d}{dx}{\left[\int f(x)dx\right]}=f(x)\]

2. \[\int cf(x)dx=c\int f(x)dx\]

3. \[\int(u+v-w)dx=\int udx+\int vdx-\int wdx\]

Important Questions [131]

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