Advertisements
Advertisements
Question
Evaluate : ` int x^2/((x^2+4)(x^2+9))dx`
Advertisements
Solution
`int x^2/((x^2+4)(x^2+9))dx=int[-4/(5(x^2+4))+9/(5(x^2+9))]dx=int-4/(5(x^2+4))dx+int9/(5(x^2+9))dx`
`=-4/5xx1/2 tan^(-1)(x/2)+9/5xx1/3tan^(-1)(x/3)+C`
`=-2/5tan^(-1)x/2+3/5tan^(-1)x/3+C`
RELATED QUESTIONS
find : `int(3x+1)sqrt(4-3x-2x^2)dx`
Find:
`int(x^3-1)/(x^3+x)dx`
Integrate the function `1/sqrt(1+4x^2)`
Integrate the function `(3x)/(1+ 2x^4)`
Integrate the function `x^2/sqrt(x^6 + a^6)`
Integrate the function `1/sqrt((x -1)(x - 2))`
Integrate the function `(5x - 2)/(1 + 2x + 3x^2)`
Integrate the function `(x + 2)/sqrt(4x - x^2)`
`int dx/sqrt(9x - 4x^2)` equals:
Integrate the function:
`sqrt(1- 4x^2)`
Integrate the function:
`sqrt(x^2 + 4x +1)`
Integrate the function:
`sqrt(1-4x - x^2)`
Find `int (2x)/(x^2 + 1)(x^2 + 2)^2 dx`
Integration of \[\frac{1}{1 + \left( \log_e x \right)^2}\] with respect to loge x is
\[\int\frac{1 + x + x^2}{x^2 \left( 1 + x \right)} \text{ dx}\]
Find : \[\int\left( 2x + 5 \right)\sqrt{10 - 4x - 3 x^2}dx\] .
Find: `int (dx)/(x^2 - 6x + 13)`
