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Question
`int dx/(x^2 + 2x + 2)` equals:
Options
x tan-1(x + 1) + C
tan-1(x + 1) + C
(x + 1) tan-1 x + C
tan-1 x + C
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Solution
tan-1(x + 1) + C
Explanation:
Let `I = int dx/(x^2 + 2x + 2)`
`= int dx/((x + 1)^2 + (1)^2)`
`= tan^-1 ((x + 1)/1) + C`
`= tan^-1 (x + 1) + C`
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\[\int\frac{8x + 13}{\sqrt{4x + 7}} \text{ dx }\]
