Advertisements
Advertisements
प्रश्न
Evaluate : ` int x^2/((x^2+4)(x^2+9))dx`
Advertisements
उत्तर
`int x^2/((x^2+4)(x^2+9))dx=int[-4/(5(x^2+4))+9/(5(x^2+9))]dx=int-4/(5(x^2+4))dx+int9/(5(x^2+9))dx`
`=-4/5xx1/2 tan^(-1)(x/2)+9/5xx1/3tan^(-1)(x/3)+C`
`=-2/5tan^(-1)x/2+3/5tan^(-1)x/3+C`
संबंधित प्रश्न
Find:
`int(x^3-1)/(x^3+x)dx`
Integrate the function `1/sqrt(1+4x^2)`
Integrate the function `(x - 1)/sqrt(x^2 - 1)`
Integrate the function `x^2/sqrt(x^6 + a^6)`
Integrate the function `1/sqrt(x^2 +2x + 2)`
Integrate the function `1/(9x^2 + 6x + 5)`
Integrate the function `1/sqrt(8+3x - x^2)`
Integrate the function `1/sqrt((x - a)(x - b))`
Integrate the function `(x + 2)/sqrt(4x - x^2)`
Integrate the function `(x + 3)/(x^2 - 2x - 5)`
Integrate the function `(5x + 3)/sqrt(x^2 + 4x + 10)`
Integrate the function:
`sqrt(x^2 + 4x + 6)`
`int sqrt(1+ x^2) dx` is equal to ______.
Find `int dx/(5 - 8x - x^2)`
Find `int (2x)/(x^2 + 1)(x^2 + 2)^2 dx`
Integration of \[\frac{1}{1 + \left( \log_e x \right)^2}\] with respect to loge x is
\[\int\frac{8x + 13}{\sqrt{4x + 7}} \text{ dx }\]
\[\int\frac{1 + x + x^2}{x^2 \left( 1 + x \right)} \text{ dx}\]
Find:
`int_(-pi/4)^0 (1+tan"x")/(1-tan"x") "dx"`
Find: `int (dx)/(x^2 - 6x + 13)`
`int (a^x - b^x)^2/(a^xb^x)dx` equals ______.
