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You Can Shield a Charge from Electrical Forces by Putting It Inside a Hollow Conductor. Can You Shield a Body from the Gravitational Influence of Nearby Matter by Putting It Inside a Hollow Sphere Or by Some Other Means

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प्रश्न

Answer the following:

You can shield a charge from electrical forces by putting it inside a hollow conductor. Can you shield a body from the gravitational influence of nearby matter by putting it inside a hollow sphere or by some other means?

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उत्तर १

No 

Gravitational influence of matter on nearby objects cannot be screened by any means. This is because gravitational force unlike electrical forces is independent of the nature of the material medium. Also, it is independent of the status of other objects.

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उत्तर २

No. Gravitational forces are independent of medium. A body cannot be shielded from the gravitational influence of nearby matter.

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 7: Gravitation - Exercises [पृष्ठ २०१]

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एनसीईआरटी Physics Part 1 and 2 [English] Class 11
अध्याय 7 Gravitation
Exercises | Q 1.1 | पृष्ठ २०१

संबंधित प्रश्न

Write the answer of the question with reference to laws of gravitation.

State the universal law of gravitation.


State Kepler’s law which is represented by the relation r3 ∝ T2.


At noon, the sun and the earth pull the objects on the earth's surface in opposite directions. At midnight, the sun and the earth pull these objects in same direction. Is the weight of an object, as measured by a spring balance on the earth's surface, more at midnight as compared to its weight at noon?


Suppose the gravitational potential due to a small system is k/r2 at a distance r from it. What will be the gravitational field? Can you think of any such system? What happens if there were negative masses?


Let V and E be the gravitational potential and gravitational field at a distance r from the centre of a uniform spherical shell. Consider the following two statements :

(A) The plot of V against r is discontinuous.
(B) The plot of E against r is discontinuous.


A person sitting in a chair in a satellite feels weightless because


Four particles of equal masses M move along a circle of radius R under the action of their mutual gravitational attraction. Find the speed of each particle.


The mass of moon is about 0.012 times that of earth and its diameter is about 0.25 times that of earth. The value of G on the moon will be:


Write an expression for the gravitational force of attraction between two bodies of masses m1 and m2 separated by a distance r.


State Newton's law of gravitation. What is the difference between:
g and G?


Answer the following question.

What are the dimensions of the universal gravitational constant?


The value of universal gravitational constant (G) in the SI unit is ______.


Mahendra and Virat are sitting at a distance of 1m from each other. Their masses are 75 kg and 80 kg respectively. What is the gravitational force between them? (G = 6.67 × 10−11 Nm2/kg2)


State the universal law of gravitation and derive its mathematical expression.


For the weight of body of mass 5 kg to be zero on equator of the earth, angular velocity of the earth must be (The radius of earth = 6400 km, acceleration due to gravity = 10 m/s2).


The force of gravitation between two bodies of mass 1 kg each separated by a distance of 1 m in vacuum is ____________.


Choose the wrong option.


Particles of masses 2M, m and M are respectively at points A, B and C with AB = ½ (BC). m is much-much smaller than M and at time t = 0, they are all at rest (Figure). At subsequent times before any collision takes place ______.


If the mass of one object is doubled and distance remains the same, the gravitational force will ______.


Who measured the value of the Universal Gravitational Constant G using the Cavendish balance?


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