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Write Lewis strucure of OX2− ion and find out oxidation state of each oxygen atom? What is the average oxidation state of oxygen in this ion?

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प्रश्न

Write Lewis strucure of \[\ce{O^{-}2}\] ion and find out oxidation state of each oxygen atom? What is the average oxidation state of oxygen in this ion?

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उत्तर

Lweis structure of \[\ce{O^{-}2}\] is   Oxygen atom with no charge has 6 electrons. Thus, its oxidation state is 0. Oxygen atom that carries negative charge has 7 electrons. Thus, its oxidation state is – 1.

Average O.S. = `(0 + (-1))/2 = (-1)/2`.

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अध्याय 10: The s-block Elements - Multiple Choice Questions (Type - I) [पृष्ठ १३०]

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एनसीईआरटी एक्झांप्लर Chemistry [English] Class 11
अध्याय 10 The s-block Elements
Multiple Choice Questions (Type - I) | Q 38 | पृष्ठ १३०

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