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प्रश्न
With the help of a neat and labelled diagram, explain the principle and working of a moving coil galvanometer ?
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उत्तर
Principle:
The working of a moving coil galvanometer is based on the fact that when a current carrying coil is placed in a magnetic field, it experiences a torque.

Working:
Suppose that a coil PQRS is suspended freely in a magnetic field.
Let l = length PQ or RS of the coil;
b = breadth QR or SP of the coil and
n = number of turns in the coil
Area of each turn of the coil, A = l × b
Let B = strength of the magnetic field in which the coil is suspended.
and I = current passing through the coil in the direction PQRS
Let α be the angle, at any instant, which the normal drawn on the plane of the coil makes with the direction of the magnetic field.
The rectangular coil carrying current, when placed in the magnetic field, experiences a torque whose magnitude is given by
τ = nIBA sinα
Due to the deflecting torque, the coil rotates and the suspension wire gets twisted. A restoring torque is set up in the suspension wire.
Let θ be the twist produced in the phosphor bronze stripe due to the rotation of the coil and let k be the restoring torque per unit twist of the phosphor bronze stripe.
Then total restoring torque produced = kθ
In equilibrium position of the coil, the deflecting torque is equal to the restoring torque.
∴ NIBA = kθ
⇒ `I = k/(NBA) Θ` 0r GΘ
Here,`k/(NBA) = G= a`
[constant for a galvanometer]
It is known as the galvanometer constant.
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संबंधित प्रश्न
An ideal voltmeter has _______.
(A) low resistance
(b) high resistance
(C) infinite resistance
(D) zero resistance
Explain how moving coil galvanometer is converted into a voltmeter. Derive the necessary formula.
A rectangular coil of a moving coil galvanometer contains 100 turns, each having area
15 cm2. It is suspended in the radial magnetic field 0.03 T. The twist constant of suspension
fibre is 15 x 10-10 N-m/degree. Calculate the sensitivity of the moving coil galvanometer.
A galvanometer has a resistance of 16Ω. It shows full scale deflection, when a current of 20 mA is passed through it. The only shunt resistance available is 0.06 which is not appropriate to convert a galvanometer into an ammeter. How much resistance should be connected in series with the coil of galvanometer, so that the range of ammeter is 8 A?
Explain, giving reasons, the basic difference in converting a galvanometer into (i) a voltmeter and (ii) an ammeter?
The current sensitivity of a galvanometer increase by 20%. If its resistance also increases by 25%, the voltage sensitivity will ______.
The coil of galvanometer consists of 100 turns and effective area of 1 square cm. The restoring couple is 10-8 N-m/rad. The magnetic field between the pole pieces is 5T. The current sensitivity of this galvanometer will be ______.
A multirange voltmeter can be constructed by using a galvanometer circuit as shown in figure. We want to construct a voltmeter that can measure 2V, 20V and 200V using a galvanometer of resistance 10Ω and that produces maximum deflection for current of 1 mA. Find R1, R2 and R3 that have to be used.

