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प्रश्न
With the help of a neat and labelled diagram, explain the principle and working of a moving coil galvanometer ?
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उत्तर
Principle:
The working of a moving coil galvanometer is based on the fact that when a current carrying coil is placed in a magnetic field, it experiences a torque.

Working:
Suppose that a coil PQRS is suspended freely in a magnetic field.
Let l = length PQ or RS of the coil;
b = breadth QR or SP of the coil and
n = number of turns in the coil
Area of each turn of the coil, A = l × b
Let B = strength of the magnetic field in which the coil is suspended.
and I = current passing through the coil in the direction PQRS
Let α be the angle, at any instant, which the normal drawn on the plane of the coil makes with the direction of the magnetic field.
The rectangular coil carrying current, when placed in the magnetic field, experiences a torque whose magnitude is given by
τ = nIBA sinα
Due to the deflecting torque, the coil rotates and the suspension wire gets twisted. A restoring torque is set up in the suspension wire.
Let θ be the twist produced in the phosphor bronze stripe due to the rotation of the coil and let k be the restoring torque per unit twist of the phosphor bronze stripe.
Then total restoring torque produced = kθ
In equilibrium position of the coil, the deflecting torque is equal to the restoring torque.
∴ NIBA = kθ
⇒ `I = k/(NBA) Θ` 0r GΘ
Here,`k/(NBA) = G= a`
[constant for a galvanometer]
It is known as the galvanometer constant.
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संबंधित प्रश्न
The fraction of the total current passing through the galvanometer is ............ .
a) `S/(S+G)`
b) `G/(S+G)`
c) `(S+G)/G`
d) `(S+G)/S`
Why does a galvanometer when connected in series with a capacitor show a momentary deflection, when it is being charged or discharged?
How does this observation lead to modifying the Ampere's circuital law?
Hence write the generalised expression of Ampere's law.
Define the current sensitivity of a galvanometer ?
Why are the pole pieces of a horseshoe magnet in a moving coil galvanometer made cylinder in shape?
The coil of a moving coil galvanometer is wound over a metal frame in order to ______.
A galvanometer of resistance 100 Ω gives a full-scale deflection for a current of 10−5 A. To convert it into an ammeter capable of measuring up to 1 A we should connect a resistance of ______.
A galvanometer having a coil resistance of 60 Ω shows full-scale deflection when a current of 1.0 amp passes through it. It can be converted into an ammeter to read currents up to 5.0 amp by:
A moving coil galvanometer of resistance 55 Ω produces a full scale deflection for a current of 250 mA. How will you convert it into an ammeter with a range of 0 - 3A?
The figure below shows a circuit containing an ammeter A, a galvanometer G and a plug key K. When the key is closed:

