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प्रश्न
With the help of a neat and labelled diagram, explain the principle and working of a moving coil galvanometer ?
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उत्तर
Principle:
The working of a moving coil galvanometer is based on the fact that when a current carrying coil is placed in a magnetic field, it experiences a torque.

Working:
Suppose that a coil PQRS is suspended freely in a magnetic field.
Let l = length PQ or RS of the coil;
b = breadth QR or SP of the coil and
n = number of turns in the coil
Area of each turn of the coil, A = l × b
Let B = strength of the magnetic field in which the coil is suspended.
and I = current passing through the coil in the direction PQRS
Let α be the angle, at any instant, which the normal drawn on the plane of the coil makes with the direction of the magnetic field.
The rectangular coil carrying current, when placed in the magnetic field, experiences a torque whose magnitude is given by
τ = nIBA sinα
Due to the deflecting torque, the coil rotates and the suspension wire gets twisted. A restoring torque is set up in the suspension wire.
Let θ be the twist produced in the phosphor bronze stripe due to the rotation of the coil and let k be the restoring torque per unit twist of the phosphor bronze stripe.
Then total restoring torque produced = kθ
In equilibrium position of the coil, the deflecting torque is equal to the restoring torque.
∴ NIBA = kθ
⇒ `I = k/(NBA) Θ` 0r GΘ
Here,`k/(NBA) = G= a`
[constant for a galvanometer]
It is known as the galvanometer constant.
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संबंधित प्रश्न
Show that the current flowing through a moving coil galvanometer is directly proportional to the angle of deflection of coil.
Why does a galvanometer show a momentary deflection at the time of charging or discharging a capacitor? Write the necessary expression to explain this observation.
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(A) low resistance
(b) high resistance
(C) infinite resistance
(D) zero resistance
Explain how moving coil galvanometer is converted into a voltmeter. Derive the necessary formula.
Write current sensitivity of a galvanomete S.I. unit.
A coil of radius 10 cm and resistance 40 Ω has 1000 turns. It is placed with its plane vertical and its axis parallel to the magnetic meridian. The coil is connected to a galvanometer and is rotated about the vertical diameter through an angle of 180°. Find the charge which flows through the galvanometer if the horizontal component of the earth's magnetic field is BH = 3.0 × 10−5 T.
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The coil of galvanometer consists of 100 turns and effective area of 1 square cm. The restoring couple is 10-8 N-m/rad. The magnetic field between the pole pieces is 5T. The current sensitivity of this galvanometer will be ______.
A multirange current meter can be constructed by using a galvanometer circuit as shown in figure. We want a current meter that can measure 10 mA, 100 mA and 1A using a galvanometer of resistance 10 Ω and that prduces maximum deflection for current of 1mA. Find S1, S2 and S3 that have to be used

A resistance of 3Ω is connected in parallel to a galvanometer of resistance 297Ω. Find the fraction of current passing through the galvanometer.
