Question

In an ammeter 0.5% of main current passes through galvanometer; If resistance of galvanometer is G, the resistance of ammeter will be.

विकल्प

• G/200

• G/199

• 199 G

• 200 G

Answer 1

G/199

Explanation:

Here Ig = 0.5% of I = 0.005 I

Is = I – Ig = 1 – 0.005 I = 0.995 I

S = `(IgG)/(Is) = (0.0051 xx G)/0.9951 = G/199`